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UkoKoshka [18]
1 year ago
12

I need help with this question, please. This is non graded.

Mathematics
1 answer:
zaharov [31]1 year ago
5 0

The rule of the volume of the rectangular prism is

V=L\times W\times H

L is the length

W is the width

H is the height

From the attached picture we can see

L = (2x - 3)

W = (x + 1)

H = (3x + 4)

We will substitute them in the rule above

V=(2x-3)(x+1)(3x+4)

We will multiply the first 2 brackets, then multiply the answer by the 3rd bracket

\begin{gathered} (2x-3)(x+1)=(2x)(x)+(2x)(1)+(-3)(x)+(-3)(1) \\ (2x-3)(x+1)=2x^2+2x-3x-3 \\ (2x-3)(x+1)=2x^2-x-3 \end{gathered}

Multiply this answer by the 3rd bracket

\begin{gathered} (2x^2-x-3)(3x+4)= \\ \left(2x^2\right)\left(3x\right)+\left(2x^2\right)\left(4\right)+\left(-x\right)(3x)+(-x)(4)+(-3)(3x)+(-3)(4)= \\ 6x^3+8x^2-3x^2-4x-9x-12= \\ 6x^3+5x^2-13x-12 \end{gathered}

Then the volume of the prism is

V=6x^3+5x^2-13x-12

The answer is the 2nd choice

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Answer:

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Step-by-step explanation:

11 is your answer

8 0
3 years ago
The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 73 minutes and a standard devi
Vesnalui [34]

Answer:

(a) X\sim N(\mu = 73, \sigma = 16)

(b) 0.7910

(c) 0.0401

(d) 0.6464

Step-by-step explanation:

Let <em>X</em> = amount of time that people spend at Grover Hot Springs.

The random variable <em>X</em> is normally distributed with a mean of 73 minutes and a standard deviation of 16 minutes.

(a)

The distribution of the random variable <em>X</em> is:

X\sim N(\mu = 73, \sigma = 16)

(b)

Compute the probability that a randomly selected person at the hot springs stays longer than 60 minutes as follows:

P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

P(60

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

6 0
3 years ago
A factory's worker productivity is normally distributed. one worker produces an average of 77 units per day with a standard devi
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Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.

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4 0
3 years ago
What is the simplest form of x²+5x-6/x²+9x+18
Lyrx [107]

Answer:

(x - 1) / (x + 3).

Step-by-step explanation:

x²+5x-6/x²+9x+18

Factoring top and bottom:

= (x + 6)(x - 1) / (x + 6)(x + 3)   (x + 6) is common, so:

= (x - 1) / (x + 3) (answer).

4 0
3 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = &lt;-5, -4&gt;, v = &lt;-4, -3&gt; (1 point)
sesenic [268]

Angle between u = -5i-4j , v=-4i-3j is x =0° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3>  or , u = -5i-4j , v=-4i-3j

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

u.v =|u|(|v|)cosx , where x is angle between u & v !

⇒ u.v =|u|(|v|)cosx

⇒ cosx =\frac{u.v}{|u|(|v|)}

Now , u.v = (-5i-4j)(-4i-3j)

⇒ u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)

⇒ u.v = 20+12            { i(j) = j(i) =0  }

⇒ u.v = 32

Now , Modulus of any vector  r = xi+yj is |r| = \sqrt{x^{2}+y^{2}} So ,

|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5

Putting all these values in equation cosx =\frac{u.v}{|u|(|v|)} we get:

⇒ cosx =\frac{32}{5(\sqrt{41})}

⇒ cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})

⇒ x =cos^{-1}(1)                 { cos0 = 1  }

⇒ x =0°

Therefore , Angle between u = -5i-4j , v=-4i-3j is x =0° .

8 0
3 years ago
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