1) 5t^2 (1 + 6t)
2) 4x^3y^5 (5x + 2y)
3) (5r + 6x)(5r - 6x)
4) (x + 10)(x - 10)
5) (x - 3)^2
6) (x -5)(x - 3)
7) 3(16r^3 + 9)
8) 8(c^3 + 8d^3)
9) (2r - 125)(4r^2 + 250r + 15625)
10) (c + 3)(c - 1)
Answer:
Secure a future for upcoming generation
Answer:
The equation of the least-squares regression line for this plot is approximately ŷ = 3.8 + two thirds times x.
Step-by-step explanation:
Answer:
The roots of the equation is real and repeated
Step-by-step explanation:
Here, we want to describe the nature of the roots of the given quadratic equation
To get the nature of the roots, we find the discriminant of the equation
The discriminant is;
b^2 - 4ac
In this case, b = -28 , a = 49 and c = 4
The discriminant is thus;
-28^2 - 4(49)(4)
= 784 - 784 = 0
Since the discriminant is zero, this means that the quadratic equation has real roots which are the same
First things first, write out your equation without the substitution.
2x+ 2y= 10
Now, put in the substitution.
2x+ 2• 2= 10
Combine like terms.
2x+ 4= 10
Now that your equation it simplified, you need to reverse the problem and put everything on the other side.
2x+ 4= 10
- 4 - 4
2x = 6
2x=6
— —
2 2
X= 3
So the final answer is x=3