Expanding (2x² + y²)⁴ with Pascal triangle or using binomial theorem gives:
(2x² + y²)⁴ = 16x⁸ + 32x⁶y² + 24x⁴y⁴ + 8x²y⁶ + y⁸
Answer:
y=2x+1
Step-by-step explanation:
Answer:
a) S = {1, 2, 3}
b) P(odd number) = 
c) No
d) Yes
Step-by-step explanation:
a) The sample space is the set of all possible outcomes. By definition, the elements of a set should not be repeated. Hence, the sample space S = {1, 2, 3}
However, the sample is not equiprobable because each element has different probabilities.
b) P(odd number) = 
Note that the odd numbers are 1 (on three faces) and 3 (on one face).
c) The fact the die has been biased does not change the possible outcomes. It only changes the probability of getting any given number.
d) Because the 3-face has been loaded, this probability changes. In fact, it is calculated thus:
Let's assume the probability for 1 or 2 is
. Then that of 3 is
(because it is twice the others). The sum of probabilities must be 1.



P(odd number) =
Prob(1) + Prob(3)
=
= 
9514 1404 393
Answer:
- 90 student tickets
- 65 adult tickets
Step-by-step explanation:
For many "mixture" problems, it is convenient to use a variable for the quantity of the highest contributor. Here, we can use 'a' to represent the number of adult tickets, because adult tickets cost the most. Then the number of student tickets is (a+25), and the total revenue is ...
6a +3(a+25) = 660
9a +75 = 660
9a = 585
a = 65
(a+25) = 90
The drama class sold 90 student tickets and 65 adult tickets.
Halting each time. 32, 16, 8