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3 years ago

The area of the figure

Mathematics

1 answer:

muminat3 years ago

7 0

Answer: Go to JW.org.

Step-by-step explanation: Its where you can find all your reliable answers.

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What is the measure of major B 84° O 276° O252° O 84° O 168 arc AB? A

alekssr [168]

Answer:

A - 84°

Step-by-step explanation:

The measure of an arc is equal to the measure of the central angle that intersects it.

The central angle of this circle measures 84° and it intercepts arc AB, meaning arc AB measures 84°

4 0

2 years ago

Solve the system of equation

Phoenix [80]

Answer:

plain = $10.50

pepperoni = $12.50

Step-by-step explanation:

x = pepperoni

y = plain

3x + 2y = 58.5

2x + 4y = 67

using substitution method, I multiplied the first system by -2 to get:

-6x - 4y = -117

+ 2x + 4y = 67

-4x = -50

x = $12.50

2(12.5) + 4y = 67

25 + 4y = 67

4y = 42

y = $10.50

7 0

3 years ago

PLEASE HELP ASAP!! I will give brainliest

Olin [163]

Answer:

Part A: Data summary is given in the table

Part B: out of the total 100 students, 15 students do not like either tennis or track

$\frac{15}{100}$ = 0.15

0.15 × $\frac{100}{100}$ = 15%

Part C:

Total no. of students that dislike track = 60

Total no. of students that dislike tennis = 40

According to the survey results, more people dislike track.

6 0

3 years ago

Read 2 more answers

Evaluate 6 C 3 . 18 20 60 120

Novosadov [1.4K]

The answer will be 6 x 5 x 4 / 3 x 2 x 1, 5 x 4 = 20. Hope this helps

5 0

4 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago