Could I have help on number 7

Mathematics

2 answers:

otez555 [7]3 years ago

7 0

M<AQG = y
m<HQE = 2y
first you need to find y=?

EF is a straight line
m<FQG = 90
so
m<HQE = 180 - 90 - 21 - y
2y = 180 - 90 - 21 - y
3y = 69
y = 23

m<HQE = 2y = 2 (23) = 46

m<AQG = y = 23

frutty [35]3 years ago

6 0

Y= 21 so HQE = 42 and AQG= 21

You might be interested in

A wise man once said 400 reduced by 3 times my age is 112 what is his age

krek1111 [17]

400-3x=112
3x=400-112=288
x=96
He is 96 years old.

6 0

3 years ago

What is the value of x? 2y + 4 10 + 2x 10+18

EastWind [94]

Answer:

if its all one equation x = -y - 22

Step-by-step explanation:

2y + 4 + 10+ 2x + 10 + 18

2x + 2y + 44

2x = -2y - 44

x = -y - 22

4 0

3 years ago

Help please!! I’ll give brainliest.....

KatRina [158]

This means the shape will move 2 grids to the right, and 2 to the top. Point A will be about (2, 5)

3 0

3 years ago

Read 2 more answers

What is thr difference between dividing 16 by 2 and finding the square roots of 16?

kenny6666 [7]

When you divide a number by two, you find the number that if you add it to itself, become the original number.

When you square root a number, you find the smaller number that becomes the bigger number if you multiply it by itself.

For sixteen, if you divide it by two, you get 8, while if you square root it, it becomes 4.

5 0

3 years ago

Read 2 more answers

What is the oblique asymptote of the function f(x) x^2+x-2/x+1

Mamont248 [21]

$f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}
$

$\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
=0$

Consequently, the limit of $f(x)$ as x approaches infinity is $x$ .

In other words, $f(x)$ approaches the line y=x,

so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.

3 0

3 years ago