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2 years ago

The vertex of this parabola is at (-5, -2). When the x-value is -4, the

Mathematics

1 answer:

tiny-mole [99]2 years ago

8 0

Answer:4

Step-by-step explanation:

The equation of a vertical parabola is:

y = a (x − h)² + k,

where (h, k) is the vertex and a is the coefficient.

We know the vertex is (-5, -2), so:

y = a (x − (-5))² + (-2)

y = a (x + 5)² − 2

We also know the parabola passes through (-4, 2).

2 = a (-4 + 5)² − 2

2 = a (1)² − 2

2 = a − 2

a = 4

So the coefficient of the squared expression is 4.

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17x-3y=4 2x-4y=1 the solution to the system of equations is

Burka [1]

ANSWER

$x=\frac{13}{62}$

and

$y= \frac{-9}{62}$ e have

EXPLANATION

$17x-3y=4---(1)$

$2x-4y=1$

Let us make y the subject and call it equation (2)

$2x=1+4y$

$x=\frac{1}{2}+2y--(2)$

We put equation (2) in to equation (1)

$17(\frac{1}{2}+2y)-3y=4$

$\frac{17}{2}+34y-3y=4$

$34y-3y=4- \frac{17}{2}$

Simplify to get,

$31y= \frac{8-17}{2}$

$31y= \frac{-9}{2}$

Divide both sides by 31,

$y= \frac{-9}{2} \div 31$

$y= \frac{-9}{2} \times \frac{1}{31}$

$y= \frac{-9}{62}$

We put this value in to equation (2) to get,

$x=\frac{1}{2}+2\times -\frac{9}{62}$

$x=\frac{1}{2} -\frac{18}{62}$

We collect LCM to obtain,

$x=\frac{31-18}{62}$

$x=\frac{13}{62}$

7 0

2 years ago

Solve each rational equation

quester [9]

The answer would be x= 4,-4

8 0

3 years ago

Find the general indefinite integral. (use c for the constant of integration. )

Vlada [557]

The indefinite integral will be $\int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)$

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

To know more about indefinite integral follow

brainly.com/question/27419605

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7 0

2 years ago

Which expression is equivalent to is m4?<br> m2+m3<br> m1+m2<br> m1+m3<br> m5+ m6

Airida [17]

Answer: m1+m3

Step-by-step explanation: 1+3=4 and m1+m3 has the same varibles in the expression.

8 0

2 years ago

Find the y-intercept of the function: f(×)=(×+10)/(×-5)

ArbitrLikvidat [17]

Answer:

(-10,0)

Step-by-step explanation:

Hello

this is (-10,0) point

because f(-10)=0

hope this helps

4 0

3 years ago

Read 2 more answers