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2 years ago

Can anyone help me with this problem?

Mathematics

1 answer:

maria [59]2 years ago

4 0

So Angle x is actually the same as angle BCA

So what you have to do is get that first

41+102+x=180

x=37

That is due to BAC and BCA being AIA (alternate interior angles)

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(-3*10^9)(1.27*10^-12) in scientific notation

katen-ka-za [31]

It would be = -3.81 * 10^-3

7 0

3 years ago

A reindeer can run 96 miles in 3 hours at this rate how far can a reindeer run in 1hour explain

jekas [21]

This is how you do it: you put mile 96 over 3 and if u wanna know how many it will run in 1 hour. You cross multiply so you multiply 96 times1 and you get 96 but now you have to divide it by 3. If you do that you'll get the answer which is 32. There are other ways to do it but I just think it's way easier this way

6 0

2 years ago

Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y

DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

$\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}$

And:

$y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}$

If we apply these two to our initial expression, we can rewrite it as:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

$\sqrt{y^3} + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}$

Here we can use the second simplification again, to rewrite:

$\sqrt{y^3} = y*\sqrt{y}$

So, concluding, we have:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}$

Then the correct option is C.

8 0

2 years ago

Would you mind the window ?

kondor19780726 [428]

I don’t know can I ???

5 0

2 years ago

Answer and how to do it

ollegr [7]

Answer:

$(x - 9)^2 + y^2 = 36$

Step-by-step explanation:

The equation of a circle in standard form is

$(x - h)^2 + (y - k)^2 = r^2$

You are given

$x^2 + y^2 - 18x + 45 = 0$

In order to put the equation in standard from, we need to complete the square. Since there is no y term, the y part is simply y^2, and there is no need to complete the square for y. For x, we do have an x term, so we must complete the square in x.

Start by grouping the x terms and subtracting 45 from both sides.

$x^2 - 18x + y^2 = -45$

Now we need to complete the square for x.

$x^2 - 18x ~~~~~~+ y^2 = -45$

The number that completes the square will go in the blank above, and it will also be added to the right side of the equation.

To find the number you need to add to complete the square, take the coefficient of the x term. It is -18. Divide it by 2. You get -9. Now square -9 to get 81. The number that completes the square in x is 81. Now you add it to both sides of the equation.

$x^2 - 18x + 81 + y^2 = -45 + 81$

$(x - 9)^2 + y^2 = 36$

Answer: $(x - 9)^2 + y^2 = 36$

6 0

2 years ago