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2 years ago

Y= -2x+34 simplified

Mathematics

2 answers:

Dima020 [189]2 years ago

8 0

Hey there!

$Answer:\boxed{x=\frac{-1}{2}y+17}\boxed{y=-2x+34}$

$Explanation:$

$y=-2x+34$

flip the equation.

$-2x+34=y$ flip the equation.

Now add -34 to both sides of the equation.

$-2x+34+-34=y+-34\\-2x=y-34$ add -34 to both sides of the equation.

In our third/last step, we will divide both sides of the equation by -2.

$\frac{-2x}{-2}=\frac{y-34}{-2}$ divide both sides of the equation by -2.

$x=\frac{-1}{2}y+17$ The answer to your equation.

There is nothing to solve for y because the equation was equal to y.

Hope this helps!

$\text{-TestedHyperr}$

jonny [76]2 years ago

4 0

<h2>Answer:</h2><h2>2(x+17)</h2><h2>Step-by-step explanation:</h2>

To be honest I am not sure

Good Luck Sorry if it is wrong.

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3 years ago

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2 years ago

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Answer:

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Step-by-step explanation:

1 inch = 36 miles.

First, find the measurement of miles for 1/4 inch. Divide 36 with 4:

36/4 = 9

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Next, find the amount of measurement of miles per 4 inches:

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Finally, combine the two measurements together:

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2 years ago

Read 2 more answers

Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a

Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = $5*sin(\frac{2*\pi*t}{15} )+6$

When Jamie is 9 meters above the ground and rising we have

9 = $5*sin(\frac{2*\pi*t}{15} )+6$ or 3/5 = $sin(\frac{2*\pi*t}{15} )$ = 0.6

which gives sin⁻¹(0.6) = 0.643 = $\frac{2*\pi*t}{15}$

from where t = 1.536 s

Therefore Jamie is gaining altitude at

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ 1.676 m/s.

(b) Jamie is rising most rapidly when the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

$\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15})$ =0, π, 2π

Therefore $-sin(\frac{2\pi t}{15} )$ = 0 whereby t = 0 or

$\frac{2\pi t}{15}$ = π and t = 7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ - 2/3π m/s which is decreasing

so we try at t = 15 s and we have $\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pi$ m/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

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Answer:

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