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2 years ago

Classify each number according to its value.

Mathematics

1 answer:

Tems11 [23]2 years ago

6 0

Answer:See below and attached

Step-by-step explanation:

Given numbers

4.2×10^-6, 2.1×10^-3, 3.1×10^-2, 3.2×10^-5, 3.5×10^-4, 5.8×10^-3, 5.2×10^-4

Greater than 3.1×10^-3

3.1×10^-2, 5.8×10^-3

Between 3.1 × 10^-3 and 4.3 × 10^-5

2.1×10 ^-3, 3.5×10^-4, 5.2×10^-4

Less than 4.3 × 10^-5

4.2×10^-6, 3.2×10^-5

Step-by-step explanation

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In figure 2, find x if the perimeter is 4. Does each answer make sense? Why or why not?

stealth61 [152]

The value of x is equal to 1.5.

It is required to find x.

<h3>What is quadratic equation?</h3>

Any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power. The quadratic formula to solve a quadratic equation ax2 + bx + c = 0 is x = [-b ± √(b2 - 4ac)]/2a.

Given that:

So for the triangle, the perimeter would be:

$(x^{2} +x+3)+(x^{2} +2x-2)+(x^{2} +2x-9)=4$

By solving in above equation, we get

$(x^{2} +x+3)+(x^{2} +2x-2)+(x^{2} +2x-9)=4\\\\\\\2x^{2}+5x-8=4\\\\2x^{2}+5x-12=0\\\\2(x + 4)(x - 1.5)=0\\\\ x=-4\\\\ x=1.5$

So, we take x= 1.5 and neglect -4 because we can't take negative roots of the quadratic equation.

Hence, the value of x is equal to 1.5.

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2 years ago

Please solve for x.<br> 43x+1 = 45

Jet001 [13]

Answer:

x=44/43

Step-by-step explanation:

Subtract 1 from both sides

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3 years ago

Including 6% sales tax, an inn charges $135.68 per night. Find the inns nightly cost

Andru [333]

135.68(1+0.06)^1= 144

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3 years ago

Read 2 more answers

Solve in attachment....

olga2289 [7]

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

$\displaystyle \int_{0} ^{1} 5x \sqrt{x} dx$

use constant integration rule which yields:

$\displaystyle 5\int_{0} ^{1} x \sqrt{x} dx$

notice that we can rewrite √x using Law of exponent therefore we obtain:

$\displaystyle 5\int_{0} ^{1} x \cdot {x}^{1/2} dx$

once again use law of exponent which yields:

$\displaystyle 5\int_{0} ^{1} {x}^{ \frac{3}{2} } dx$

use exponent integration rule which yields;

$\displaystyle 5 \left( \frac{{x}^{ \frac{3}{2} + 1 } }{ \frac{3}{2} + 1} \right) \bigg| _{0} ^{1}$

simplify which yields:

$\displaystyle 2 {x}^{2} \sqrt{x} \bigg| _{0} ^{1}$

recall fundamental theorem:

$\displaystyle 2 ( {1}^{2}) (\sqrt{1} ) - 2( {0}^{2} )( \sqrt{0)}$

simplify:

$\displaystyle 2$

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our answer is A

8 0

3 years ago

Read 2 more answers

How do you do this question?

vaieri [72.5K]

Answer:

(-∞, -2), (-2, -0.618), and (1.618, 3)

Step-by-step explanation:

The red plus (+) signs indicate the regions in which the function is concave up, and the red negative (-) signs indicate the regions in which the function is concave down.

Note that the sign of the concavity changes at an inflection point.

Let's examine the intervals given.

(-∞, -2): Yes, concave up.

(-∞, -1.17): No. Concave up in (-∞, -2) but concave down in (-2, -1.17).

(-2, 0): No. Concave down in (-2, -1.17) but increasing in (-1.17, 0.0).

(-1.17, 0.689): Yes. Concave up.

(-0.618, 1.618): No. Concave up in (-0.618, 0.689) but concave down in (0.689, 1.618).

(0, 3): No. Concave up in (0, 0.689), concave down in (0.689, 2.481), and concave up in (2.481, 3).

(2.481, ∞): Yes. Concave up.

The three intervals that are concave up are (-∞, -2), (-1.17, -0.689), and (2.481, ∞).

4 0

3 years ago