Question

Write a formula for the sequence of cube numbers: 1, 8, 27, 64, ….

Answer 1

Answer: $n^3$, where n = 1,2,3,4,.....

Step-by-step explanation:

The given sequence : 1, 8, 27, 64, ….

We observe that the terms are perfect cubes of consecutive integers (starting from 1) .

Terms can be written as:

First term =  $a_1=1=1^3$

Second term=$a_2=8=2^3$

Third term = $a_3=27=3^3$

Fourth term =$a_4=64=4^3$

Thus , for any nth term ,the formula for the sequence is : $n^3$, where n = 1,2,3,4,.....