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denpristay [2]
3 years ago
12

Solve this: (a^3-2a^2)-(3a^2-4a^3)

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0
(a^3-2a^2)-(3a^2-4a^3)
(a^3-2a^2)-3a^2+4a^3
5a^3-5a^2
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The sum of Ali and Mel's age is 39. If Mel is 3 years younger than twice Ali's age, how old is Mel?
olga55 [171]

Answer:

Age of Mel is 25 years.

Step-by-step explanation:

It is given that,the sum of Ali and Mel's age is 39. If Mel is 3 years younger than twice Ali's age.

Let 'x' be the Ali's age  and 'y' be the Mel's age

<u>To find the value of x and y</u>

sum of Ali and Mel's age is 39

⇒ x + y = 39    ------(1)

  Mel is 3 years younger than twice Ali's age

⇒ y = 2x - 3   -------(2)

⇒  2x - y = 3  -----(3)

(1) + (3) ⇒  

 x + y = 39

2x - y = 3

----------------

3x   = 42

x = 42/3 = 14

y = 2x - 3 = 14*2 - 3  = 25

Therefore the age of Ali = 14

Age of Mel = 25

4 0
3 years ago
Jeremy has $120 in his saving account. Katie had $180 in her account. Each week Jeremy adds $14.00 to his account and Katie adds
valkas [14]

Answer:

15 weeks

Step-by-step explanation:

Let the number of weeks = x.

At the end of x weeks,

Jeremy has 120 + 14x,

and Katie has 180 + 10x

We want to know when their amounts are equal.

120 + 14x = 180 + 10x

4x = 60

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Answer: 15 weeks

8 0
3 years ago
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Which two functions are inverses of each other?
liraira [26]

Answer:

Option 3 - f(x)= 4x, g(x) = \frac{1}{4}x

Step-by-step explanation:

To find : Which two functions are inverses of each other?

Solution :

Two functions are inverse if f(g(x))=x=g(f(x))

Now, we find one by one

1) f(x)= x, g(x) = -x

f(g(x))=f(-x)=-x\neq x

Not true.

2) f(x)= 2x, g(x) = -\frac{1}{2}x

f(g(x))=f(-\frac{1}{2}x)=2\times(-\frac{1}{2}x)=-x\neq x

Not true.

3) f(x)= 4x, g(x) = \frac{1}{4}x

f(g(x))=f(\frac{1}{4}x)=4\times(\frac{1}{4}x)=x

g(f(x))=f(4x)=\frac{1}{4}\times 4x=x

i.e. f(g(x))=x=g(f(x)) is true.

So, These two functions are inverse of each other.

4) f(x)= -8x, g(x) =8x

f(g(x))=f(8x)=8\times(-8x)=-64x\neq x

Not true.

Therefore, Option 3 is correct.

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3 years ago
Geometry Chapter 4 review
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