All categories

2 years ago

Solve this: (a^3-2a^2)-(3a^2-4a^3)

Mathematics

1 answer:

Jobisdone [24]2 years ago

6 0

(a^3-2a^2)-(3a^2-4a^3)
(a^3-2a^2)-3a^2+4a^3
5a^3-5a^2

You might be interested in

Jose desea cubrir los gastos del tratamiento del Cov.19 de un familiar,para ello solicita un préstamo de una entidad bancaria un

sveta [45]

Answer:

Step-bynznsbsjsjsbsisksbbd-step explanation:bdndnsoansjj hi rodn

5 0

2 years ago

Read 2 more answers

Someone help me. Please answer correctly

Goryan [66]

I believe that the answer is 14 or 7

8 0

2 years ago

Read 2 more answers

if a cylinder has a volume of 75 cubic inches, what would be the volume of a cone with the same base and height? Explain

kumpel [21]

25 cubic inches because you know that every cone is a third of the volume of the cylinder with which it shares a height and base with.

3 0

2 years ago

Approximate the logarithm using the properties of logarithms, given

Alekssandra [29.7K]

Answer:

-0.2084

Step-by-step explanation:

$log_{b}( \frac{2}{3} ) \\ \\ = log_{b}(2) - log_{b}(3) \\ \\ =0.3562 - 0.5646 \\ \\ = -0.2084$

4 0

2 years ago

The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a

horrorfan [7]

Answer:

Assuming population data

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$s = \sqrt{0.000425}=0.0206$

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

$\mu = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}$

And we got $\sigma^2 =0.000354$

And the deviation would be just the square root of the variance:

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$\bar X = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}$

And we got $s^2 =0.000425$

And the deviation would be just the square root of the variance:

$s = \sqrt{0.000425}=0.0206$

6 0

3 years ago