3 years ago

Consider the equation:

Mathematics

1 answer:

Alenkasestr [34]3 years ago

5 0

Answer:

the equation is not correct....

well, it should look sth. like (x+or- number)^2=number

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Answer:

Following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

In the given equation, when the point t=0

So,

$\to r(0) = (3 \cos 0)i + (0^4 - 6 \sin 0)j + (2e^{3\times 0})k)$

$= (3 \times 1)i + (0 - 0)j + (2e^{0})k)\\\\ = 3i + 0j + (2 \times 1)k)\\\\ = 3i + 0j + 2k \\$

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