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ikadub [295]
3 years ago
9

Can someone help me with this please

Mathematics
1 answer:
qaws [65]3 years ago
7 0

Answer:

1. Answer is C

4. Answer is G

Step-by-step explanation:

I'm not sure how to explain 1 since I used a calculator.

Number 4 is where you choose a point on the line and count 4 blocks up and 5 blocks left. If it hits another point on the line then that's the graph.

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Question 1. Enter the ratio equivalent to sin(B)
Deffense [45]

Answer:

The three questions about the given triangle has been answered below.

Step-by-step explanation:

We are given a right angled triangle whose sides are of length 20, 21 and 29.

<u>(1)</u> sin(B) = \frac{side opposite to B}{hypotenuse}

              = \frac{21}{29}

              = 0.72

<u>(2)</u> sin(A) = \frac{20}{29}

     sin(A)  = 0.689

     ∠CAB = sin^{-1}(0.689)

     ∠CAB = 43.551°

<u>(3)</u> We suppose that cosA < sinA and we haveto find which all angles will satisfy this condition.For this the angle A should be greater than 45°.

From the given options the angles that satisfy this are 55 , 66 and 75.

45 is not included as then sinA = cosA and that condition is not there.

8 0
3 years ago
Solve for x. What is x/15 = 21/5?​
melisa1 [442]

Answer: x = 63

Step-by-step explanation:

15/3 = 5

3 * 21 = 63

63/15 = 21/5

8 0
3 years ago
Read 2 more answers
Mr. Lopez wrote the equation 32g+8g-10g=150 on the board. Four students explained how to solve for g. Alyssa: “I added 32 and 8
Vaselesa [24]

Answer:

Wilhem

Step-by-step explanation:

The given equation is

32g+8g-10g=150

Step 1 : Add 32g and 8g.

(32g+8g)-10g=150

(32+8)g-10g=150

40g-10g=150

Step 2: Subtract 10 from 40.

(40-10)g=150

30g=150

Step 3: Divide both sides by 30, find the value of g.

\frac{30g}{30}=\frac{150}{30}

g=5

The value of g is 5.

Therefore, Wilhem is correct.

7 0
2 years ago
Read 2 more answers
Any thoughts im really confused on it
wariber [46]
In step two he flipped the fraction back to how it was originally but he was supposed to leave it improper in order to multiply
4 0
2 years ago
A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur
Vladimir79 [104]

Answer:

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The volume of the open-topped box is equal to

V=LWH

where

L=(7-2x)\ in\\W=(2-2x)\ in\\H=x\ in

substitute

V=(7-2x)(2-2x)x

Convert to expanded form

V=(7-2x)(2-2x)x\\V=(14-14x-4x+4x^{2})x\\V=14x-14x^2-4x^2+4x^{3}\\V=4x^{3}-18x^{2} +14x

using a graphing tool

Graph the cubic equation

Remember that

The domain for x is the interval -----> (0,1)

Because

If x>1

then

the width is negative (W=2-2x)

so

The maximum is the point (0.46,3.02)

see the attached figure

therefore

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

8 0
3 years ago
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