John will pay $8.68 for the combined cost of 1 pound of banana and 1 pound of cherries.
Let: b=cost of banana per pound and c=cost of cherries per pound
Equation 1: For 3 pounds of cherries and 2 pounds of bananas, John pays a total of $24.95.
3c + 2b =$24.95
Equation 2: The cost of bananas is $6.50 less than a pound of cherries.
b= c - $6.50
We can substitute the second equation into the first one to solve for the cost of cherries per pound.
3c + (2)(c-$6.50)= $24.95
3c + 2c -$13.00 = $24.95
5c = $24.95 + $13.00
c = $7.59
Substituting the value of c to the second equation to solve for b.
b= $7.59 - $6.50 = $1.09
The combined cost of 1 pound of banana and 1 pound of cherries is $1.09 + $7.59 or $8.68.
For more information regarding the system of equations, please refer to brainly.com/question/25976025.
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First number --- (2a-1)
middle number ---- (2a)
third number -----(2a+1)
2a-1+2a+2a+1=250
6a=250
a=250/6= 125/3
2a=2*(125/3)= 250/3 ---- is not a whole number that is contradicts to what is given, so sum cannot be 250
so
Answer:
3(4)+g=28
Step-by-step explanation:
3 is the cost of one pair of shoes and 4 is how many shoes were rented. you multiple the 3 times 4 and get 12 and to get the amount of one game you have to subtract the total amount. the equation I came up with might not be what your teacher wants but thats a start. hope it helped!
Using the AC method for factoring.....
you should get the answer of...
(3d+8)(d-3)
