Answer:
the first is non-statistical and the second one is statistical
Step-by-step explanation:
when it is statistical it is asking in general (like a yes or no question) and when it's non-statistical it is asking something specific.
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
Answer: 7/32
Step-by-step explanation:
3/8}^2=9/64
3/7+3/14=9/14
9/64÷9/14=7/32
Answer:
3
Step-by-step explanation:
The problem appears to be 35 divided by 8, which would be 4 with a remainder of 3.
We are given this inequality,
We will follow these steps to solve it:
Step 1:
First let us bring 10 to the left side.
10 is in addition on right, so we apply opposite operation of addition that is subtracting 10 from left side, we get
Step 2:
Next we have to eliminate -4 which is in multiplication with x on the right side.
So applying opposite operation of multiplication that is dividing both sides by -4.
We have to consider here that when we divide or multiply with a negative the sign of inequality reverses, that is ≥ becomes ≤ and vice versa.
x≥4
Answer is last option x≥4.
