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Vesnalui [34]
4 years ago
5

The graph of F(x) , shown below, resembles the graph of G(x) = x ^ 2 , but it has been changed somewhatWhich of the following co

uld be the equation of F(x) ?

Mathematics
1 answer:
NNADVOKAT [17]4 years ago
7 0

Answer:

B.

Step-by-step explanation:

Since we are moving the graph f(x) to the right 2 and down 1 with a reflection over the x-axis, we modify <em>a</em>, <em>h</em>, and <em>k</em> in f(x) = a(bx - h)² + k:

We would get f(x) = -(x - 2)² - 1 as our answer.

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Dmitry [639]
The leaf of the number 392 would be. 2 cause there can be a lot of numbers that begin 39. Example:-

Plot 389, 392, 395, 351, 408 on a stem-and-leaf plot:-

Stem| Leaf
 35   |1
 38   |9
 39   | 2 5 
 40   | 8

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3 years ago
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Answer:

Step-by-step explanation:

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What is the ratio of the surface areas of the similar square pyramids below?
mamaluj [8]

Step-by-step explanation:

8 times 12 is 96

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2 years ago
What is the value of x that satisfies the equation<br> 15(x + 9) = -21?
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Step-by-step explanation:

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4 0
2 years ago
The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe
juin [17]

The height of container is 8 feet

<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

v = length \times width \times height

Given that volume of the container is 216 cubic feet

216 = l \times w \times h

Substitute eqn 1 and eqn 2 in above formula

216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0

Solve by factoring

(h-8)(h^2+4h+27) = 0

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

h - 8 = 0\\\\h = 8

Also,

h^2+4h+27 = 0

Solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}

h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}

Therefore, on solving we get,

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

<em><u>Thus solutions of "h" are:</u></em>

h = 8

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0
3 years ago
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