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3 years ago

Find x. 14 in. 48 in. X = in.

Mathematics

2 answers:

geniusboy [140]3 years ago

8 0

A^2+b^2=c^2
14^2+48^2=c^2
196+2304=c^2
2500=c^2
50=c
your answer is 50

Bad White [126]3 years ago

4 0

Answer:

x = 50 in

Step-by-step explanation:

Since it is a right triangle we can use the Pythagorean theorem

a^2 + b^2 = c^2

14^2 + 48^2 = x^2

196 + 2304 = x^2

2500 = x^2

Take the square root of each side

sqrt(2500) = sqrt(x^2)

50 =x

x = 50 in

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A car whose acceleration is constant reaches a speed of

Sergeu [11.5K]

Answer:

12.5 s

Step-by-step explanation:

If acceleration is constant, speed is proportional to time. To increase the speed by 50 km/h, the car will need an additional time given by ...

t/(50 km/h) = (20 s)/(80 km/h)

t = (20 s)(50/80) . . . . . multiply by 50 km/h

t = 12.5 s

It will take 12.5 more seconds for it to reach a speed of 130 km/h.

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3 years ago

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The Russo-Japanese War was a conflict between Russia and Japan that started in the year 190419041904. Let xxx represent any year

wel

The first thing we must do for this case is to define a variable.
We have then:
x: number of years before the Russo-Japanese conflict began
We write now the inequality that models the problem.
We know that the conflict began in the year 1904, therefore, all the previous years are given by:
x <1904
Answer:
an inequality in terms of x and 1904 that is true only for values of x that represent years before the start of the Russo-Japanese War is:
x <1904

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3 years ago

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Circle theorem - find p

kow [346]

Answer:

Step-by-step explanation:

the angle in a semicircle = 90° , that is the 3rd angle in the triangle.

the sum of the 3 angles in a triangle = 180° , then

p + 90° + 42° = 180°

p + 132° = 180° ( subtract 142° from both sides )

p = 48°

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2 years ago

Write the equation of the line parallel to Y equals 2/3X +1 through the point (0,-4) use slope intercept form

Andrew [12]

Writing the slope-intercept form of a linear equation, we have:

$y=mx+b$

Where m is the slope and b is the y-intercept.

Since parallel lines have the same slope, we can see that the slope of the line y = 2/3x + 1 is equal m = 2/3, so for our equation we also have m = 2/3.

Now, using the point (0, -4), we have:

$\begin{gathered} y=\frac{2}{3}x+b \\ (0,-4)\colon \\ -4=\frac{2}{3}\cdot0+b \\ b+0=-4 \\ b=-4 \end{gathered}$

So our equation is:

$y=\frac{2}{3}x-4$

y = 2/3x - 4

7 0

1 year ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago