Find the equation of the line that is parallel to y=-3x+17 and goes through the point(-4,2)

Mathematics

1 answer:

cluponka [151]3 years ago

7 0

Answer:

y=-3x-10

Step-by-step explanation:

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the length of a rectangle is 3 times its width. the perimeter is 55. find the length and width of the rectangle

Shkiper50 [21]

Answer:

Step-by-step explanation: L= length w= width p= perimeter

L=3W p=55CM

P. of rectangle= 2(l+w)=55cm

L+w= 55/2= 27.5 cm

3w+w=27.5cm

4w=27.5cm

w=27.5/4=6.875cm w=6.875cm L= 3w=6.875*3=20.625cm

4 0

3 years ago

The diameter of a human red blood cell is 0.000009 m. The diameter of a cold virus is 0.00000003 m Approximately how many times

krek1111 [17]

Answer:

D. 3*10^2

Step-by-step explanation:

Given the diameter of human red blood cell = 0.000009 m

diameter of a cold virus = 0.00000003 m

To know how many times as large is the diameter of a red blood cell as the diameter of a cold virus, we will take the ratio of the diameter of human red blood cell to that of a cold virus as shown;

diameter of human red blood cell/diameter of a cold virus = 0.000009 m/0.00000003 m

= 9*10^-6/3*10^-8

= 9/3 * 10^-6-(-8)

= 3 * 10^(-6+8)

= 3*10^2

Hence the diameter of a red blood cell is 3*10^2 larger than that of the cold virus

8 0

3 years ago

Determine the values of the unlabeled parts of the triangle.

____ [38]

Answer:

∠Q = 63.4º, PQ = 2, QO = 4.47

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as the equilateral triangle, isosceles triangle, scalene triangle, right angled triangle.

Triangle POQ is a right angled triangle because ∠P = 90°. Also, ∠O = 26.6°.

Therefore in ΔPOQ: ∠P + ∠O + ∠Q = 180° (sum of angles in a triangle).

90 + 26.6 + ∠Q = 180

∠Q + 116.6 = 180

∠Q = 180 - 116

∠Q = 63.4°

We can find PQ and QO using sine rule. Sine rule for ΔPOQ is given as:

$\frac{PO}{sin Q}= \frac{PQ}{sinO}= \frac{QO}{sin P}\\\\Finding\ PQ :\\\\\frac{PO}{sin Q}= \frac{PQ}{sinO}\\\\\frac{4}{sin(63.4)} =\frac{PQ}{sin(26.6)}\\\\PQ= \frac{4}{sin(63.4)} *sin(26.6)\\\\PQ = 2\\\\Also\ finding\ QO:\\\\\frac{PO}{sin Q}= \frac{QO}{sinP}\\\\\frac{4}{sin(63.4)} =\frac{QO}{sin(90)}\\\\QO=\frac{4}{sin(63.4)} *sin(90)\\\\QO = 4.47$