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Nady [450]
3 years ago
13

Please help!! thanks!!

Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0

Answer:

<em><u>_________</u></em><em><u>(</u></em><em><u>A</u></em><em><u>NSWER</u></em><em><u>)</u></em><em><u>_________</u></em>

<em><u>1.</u></em><em><u>(</u></em><em><u>C</u></em><em><u>)</u></em>

<em><u>2.</u></em><em><u>(</u></em><em><u>D</u></em><em><u>)</u></em>

<em><u>3.</u></em><em><u>(</u></em><em><u>B</u></em><em><u>)</u></em>

<em><u>4.</u></em><em><u>(</u></em><em><u>A</u></em><em><u>)</u></em>

<em><u>6</u></em><em><u>.</u></em><em><u>(</u></em><em><u>D</u></em><em><u>)</u></em>

Explanation:

<em><u>(</u></em><em><u>BRAINLEIST</u></em><em><u> </u></em><em><u>PLEASE</u></em><em><u>)</u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☻</u></em><em><u>♨️</u></em><em><u>♨️</u></em><em><u>☻</u></em><em><u>☺️</u></em><em><u>❤</u></em>

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3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in
Pepsi [2]

Part A. We are given the following polynomial:

\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2

This is a polynomial of the form:

p=k(x-a)^b(x-c)^d\ldots(x-e)^f

The x-intercepts are the numbers that make the polynomial zero, that is:

\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}

The values of x are then found by setting each factor to zero:

\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}

Therefore, this values are:

\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}

In this case, the x-intercepts are:

\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.

6 0
2 years ago
ANSWER ALL THE QUESTIONS IN THIS WORKBOOK.
777dan777 [17]

Answer:

i. 15, 18, 20, 20, 25

ii.

a) 19.6

b) 20

c) 20

d) 10

Step-by-step explanation:

8 0
3 years ago
Can anybody help me solve this? You must solve for X first.
gogolik [260]

Answer:

45 degrees

Step-by-step explanation:

angle QRS is same as (2x + 3) because it is an isosceles triangle

so, 90 + (2x+3) + (2x+3) =180 degrees

             2x+3 +2x+3=180-90

2x+2x +3+3=90

4x+6=90

4x=90-6

4x=84

x=84/4

x=21

substitute x=21 in (2x+3)

2*21+3=45

6 0
3 years ago
PLEASE HELP ME!!!! Please show work!!! ASAP!!
Ber [7]
The answer would be C. because you have to multiply all of the numbers and then divide by the 90 degree angle.

5 0
3 years ago
Drag each number to the correct location on the table.
ASHA 777 [7]

Answer:

\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}

          3\sqrt{25}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sqrt{141}\\\\\sqrt{256} \\\\1. \overline{ 1625} \\\\\frac{-11}{151}

Step-by-step explanation:

Since we believe it  

The number sequence is that those which can be described as \frac{p}{q} and that is not ending and recurring.  Figures that are unreasonable are also the ones, that are not \frac{p}{q} and therefore are non-ending, non-recurring.  

The number sequence is 3\sqrt{25} = 3 \times 5 = 15

Rational amount since it is classified as \frac{p}{q}  .\frac{-11}{151} is really a rational number.  

1.\overline{1.625} is a real function, since it does not end but repeats it.  

The rational number \sqrt {256} = 16

Unreasonable number \sqrt{141}.

7 0
3 years ago
Read 2 more answers
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