What is the axis of symmetry for the function

Which of the following expressions are equivalent to \left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(9 87 +2 54 )− 21

lora16 [44]

Answer:

$12\dfrac{7}{40}$

Step-by-step explanation:

The given expression is

$\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}$

We need to find the simplified form of the given expression.

It can be rewritten as

$\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}$

Combine integers and fractions separately.

$(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})$

Taking LCM we get

$11+\dfrac{35+32-20}{40}$

$11+\dfrac{47}{40}$

In can be written as

$11+\dfrac{40+7}{40}$

$11+1+\dfrac{7}{40}$

$12+\dfrac{7}{40}$

$12\dfrac{7}{40}$

Therefore, the expression $12\dfrac{7}{40}$ is equivalent to the given expression.

5 0

3 years ago

Find the value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2

soldier1979 [14.2K]

The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

<u>Solution:</u>

Given that line is passing through point (-5, 2) and (3, r)

Slope of the line is $\frac{-1}{2}$

Need to determine value of r.

Slope of a line passing through point $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given by following formula:

$\text { Slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ --- eqn 1

$\text { In our case } x_{1}=-5, y_{1}=2, x_{2}=3, y_{2}=\mathrm{r} \text { and } m=-\frac{1}{2}$

On substituting the given value in (1) we get

$\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}$

Hence the value of "r" is -2

8 0

3 years ago

If DF=7x-3 and EG=5x+9, find the value of X

PilotLPTM [1.2K]

Answer:

$x=6$

Step-by-step explanation:

Using the given measurements of the angles and the lengths of the sides, we can determine that this figure must be a <u>rectangle</u>.

Diagonals of a rectangle are <em>always</em> equivalent/congruent.

We can use this information to set up an equation:

$DF=EG\\7x-3=5x+9$

Add 3 to both sides:

$7x-3+3=5x+9+3\\7x=5x+12$

Subtract 5x from both sides:

$7x-5x=5x-5x+12\\2x=12$

Divide both sides by 2

$\frac{2x}{2}=\frac{12}{2}\\x=6$

3 0

2 years ago

Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7

Gre4nikov [31]

<h2>The product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}$ .</h2>

Step-by-step explanation:

We have,

$\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

To find, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$ = ?

∴ $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

= $\dfrac{7x.x}{(x-4)(x+7)}$

= $\dfrac{7x^2}{(x(x+7)-4(x+7)}$

= $\dfrac{7x^2}{x^2+7x-4x-28}$

= $\dfrac{7x^2}{x^2+3x-28}$

Thus, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}$ .

7 0

3 years ago

One alloy is 2 parts iron to 3 parts silver and another alloy is 7 parts iron to 3 parts silver. How much of each should be comb

Shalnov [3]

Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!

8 0

4 years ago