Answer:
Step-by-step explanation:
So you subtracted 14 on both sides and that is your answer
Increasing the sample size by a factor of 4 or multiplying
it by 4 is equal to increasing the standard error by 1/2. Therefore, the
interval will be half as varied. This also works almost for population
averages as lengthy as the multiplier from the t-curve doesn't modify much when
increasing the sample size.
Answer:
d, e
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b
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In this case, it means the product is ...
(6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36
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The 6 without an exponent is equivalent to 6^1, an exponent of 1.
The sum of the exponents is -2.
Add the exponents to simplify the expression.
The value of the expression is 1/36.
An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).
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Only the last two choices, d and e, apply.
Answer:
hello your question is incomplete attached below is the complete question
answer :
<em>Daniels sister is not correct because the time that will be taken by Daniel will be greater than the initial total time taken by Daniel.</em>
Step-by-step explanation:
<u>First determine the time it will take Daniel to reach the Boat and the jogging time</u>
time = distance / rate
where distance can be calculated using this equation: sin 53° = 400 / x
hence x ( distance ) = 500 ft
rate = 150
therefore Time ( t ) to reach boat = 500 / 150 = 3.33 minutes
Time for jogging ( as calculated ) = 3.69 minutes
therefore total time taken by Daniel = 3.33 + 3.69 = 7.02 minutes
<u>Finally determine if Daniel's sister is correct that he should have swam to the boat ramp and then jogged </u>
lets assume Distance to swim = x ( according his sister )
determine the value of x =
therefore X = 1456.02 feet
∴
Total time to be taken if Daniel follows his sister's instruction = 1456.02 / 150 = 9.71 minutes
<em>Daniels sister is not correct because the time that will be taken by Daniel will be greater than the initial total time taken by Daniel.</em>
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