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vlada-n [284]
3 years ago
12

4) 6(1 - 8m) + 3m = 231 A) {8} B) {-9) C) (-5) D) (-10)

Mathematics
2 answers:
Mazyrski [523]3 years ago
5 0

Answer:

C - -5

Step-by-step explanation:

6( 1 - 8m) + 3m = 231

Open the bracket with 6

6*1 = 6

6*-8m = -48m

6 - 48m + 3m = 231

6 - 45m = 231

-45m = 231 - 6

-45m = 225

Divide both sides by -45

-45m/-45 = 225/-45

m = 225/-45

m = -5

Dimas [21]3 years ago
3 0

Step-by-step explanation:

6(1 - 8m) + 3m = 231

6 - 48m + 3m = 231

- 48m + 3m = 225

- 45m = 225

m =  - 5

option C

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Determine the wavelengths of all the possible photons that can be emitted from the n = 5 state of a hydrogen atom.
KonstantinChe [14]

Answer:

Wavelengths of all possible photons are;

λ1 = 9.492 × 10^(-8) m

λ2 = 1.28 × 10^(-6) m

λ3 = 1.28 × 10^(-6) m

λ4 = 4.04 × 10^(-6) m

Step-by-step explanation:

We can calculate the wavelength of all the possible photons emitted by the electron during this transition using Rydeberg's equation.

It's given by;

1/λ = R(1/(n_f)² - 1/(n_i)²)

Where;

λ is wavelength

R is Rydberg's constant = 1.0974 × 10^(7) /m

n_f is the final energy level = 1,2,3,4

n_i is the initial energy level = 5

At n_f = 1,.we have;

1/λ = (1.0974 × 10^(7))(1/(1)² - 1/(5)²)

1/λ = 10535040

λ = 1/10535040

λ = 9.492 × 10^(-8) m

At n_f = 2,.we have;

1/λ = (1.0974 × 10^(7))(1/(2)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.21)

1/λ = 2304540

λ = 1/2304540

λ = 4.34 × 10^(-7) m

At n_f = 3, we have;

1/λ = (1.0974 × 10^(7))(1/(3)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.07111)

1/λ = 780373.3333333334

λ = 1/780373.3333333334

λ = 1.28 × 10^(-6) m

At n_f = 4, we have;

1/λ = (1.0974 × 10^(7))(1/(4)² - 1/(5)²)

1/λ = (1.0974 × 10^(7))(0.0225)

1/λ = 246915

λ = 1/246915

λ = 4.04 × 10^(-6) m

5 0
3 years ago
Adult tickets to space city amusement park cost x dollars. children's tickets cost y dollars. the garcia family bought 3 adult a
3241004551 [841]
A childs ticket = $28 and an adult = $45 
Total Cost to each family is the number of adult tickets bought multiplied by "x" PLUS the number of child tickets bought multiplied by "y" 
Henson's equation = 3x + y = 163 Garcia's equation = 2x + 3y = 174 
using the substitution method we need to express either x or y in terms of the other variable. In this example looking at the Henson equation it is very easy to express y in terms of x. 
Rewrite the Henson equation to make y the subject y = 163 - 3x Substitute this value (163 - 3x) for "y" in the Garcia equation which now becomes 
2x + 3(163 - 3x) = 174 Expand the bracket 2x + 489 - 9x = 174 -7x + 489 = 174 Add 7x and subtract 174 from both sides of the equation 315 = 7x 315/7 = x 45 = x An adult ticket costs $45 Substitute this back into the Henson equation 3 * 45 + y = 163 135 + y = 163 y = 163 - 135 = 28 A childs ticket costs $28 
Check in the Garcia equation 2 * 45 + 3 * 28 = 90 + 84 = 174 = CORRECT 
A childs ticket = $28 and an adult = $45
8 0
3 years ago
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