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olchik [2.2K]
2 years ago
10

Who wants brainllest follow my tik tok .splited

Mathematics
2 answers:
sergey [27]2 years ago
7 0

Answer: do you do f4f?

Step-by-step explanation:

Anestetic [448]2 years ago
4 0

Answer:

ok check if i addes you

Step-by-step explanation:

You might be interested in
If the regular selling price of a silk scarf is $49 and the markdown rate is 38%, what is its sale price?
Aleks04 [339]

Answer:

$30.38

Step-by-step explanation:

To find the sale price, find the percentage you pay after the discount. The discount is for 38%. So you pay 62%.

The selling price of the scarf will be 0.62(49) = 30.38

4 0
3 years ago
A ratio is in its simplest form 7:9.<br>if its consequent is 117, find the antecedent​
a_sh-v [17]

Answer:

Let the income and saving rs7x and respectively 2x

then

2x=500

Step-by-step explanation:

3 0
2 years ago
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
Solve this equation! Please Help!<br><br> √3 x 66.15/4.41<br><br> (SHOW YOUR WORK)
finlep [7]
Hi Jessica,
<span>Remember PEMDAS (Parenthesis, Exponents, Multiplication & Division, Addition & Subtraction).

√3 x 66.15/4.41 {Exponents/Cube & Square Roots First}

1.73 x 66.15 ÷ 4.41 {Multiplication}

114.4395 ÷ 4.41 {Division}

25.95 {Final Answer}

Cheers,
Izzy</span>
7 0
2 years ago
Given trapezoid KLMN with midsegment EF, where KL = 4 and MN = 7, what is the length of EF?​
TEA [102]

Answer:

EF= 5.5

Step-by-step explanation:

7 + 4 = 11

11 divided by 2 = 5.5

3 0
2 years ago
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