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lukranit [14]
3 years ago
8

Candy selling at $6.00 per pound will be mixed with candy selling at $9.00 per pound. How many pounds of the more expensive cand

y are needed to produce a 15-pound mixture that sells for $7.00 per pound?
Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0
Well you need the mixture to start off by equalling $7, no matter what weight it is. The mean of two $6 candies and one $9 candy is $7 (6+6+9 = 21, 21/3 = 7)
So the ratio of 2:1 6$:9$ makes $7

Add 2 and 1 to get 3, 15/3 = 5, and because you're working out how much you need for the $9 candy, 5*1 (Because of the 2:1 ratio) is 5
She needs 5 pounds worth of the 9$ candy
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kompoz [17]
<span>No. 

To check this yourself, you need the denominators to be the same to be able to easily compare the two. 

For example, does 5/8 = 40/64? 

1. Determine what you would need to do to the denominator in 5/8 to make it 64. (Multiply it by 8) 
2. Find what fraction is equal to 1 with a denominator of 8. (8/8) 
3. Multiply the fraction 5/8 by the one you just found (8/8), numerator times numerator, denominator times denominator. 
4. Compare the answer with the second fraction. 

It is important that when you multiply the denominator by any number you multiply the numerator by the same number. This is to preserve the fraction's value. This works because any number divided by itself is equal to 1, AND when you multiply any number by 1 (whether 1 is in the form of 1 or 4/4 or 8/8 or 234/234), the answer is always equal to the original number. 

Another way to check would be to simply enter 1/2 into a calculator, write down the answer. Next enter 5/8 into a calculator. If the answers are the same, they are equal.</span><span>
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8 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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3 years ago
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2 years ago
You are traveling 75 miles per hour on the interstate. how long will it take you to travel 30 miles
Anvisha [2.4K]
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6 0
4 years ago
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