<u>The</u><u> </u><u>lines</u><u> </u><u>presented</u><u> </u><u>by</u><u> </u><u>equations</u><u> </u>
<u></u>
<u>PeRpEnDeCuLaR</u>
<u>(</u><u>Perpendicular</u><u>)</u><u> </u>
<u>#BrainliestBunch</u>
The sum of the first 13 terms is 260
<h3>How to calculate the sum of the first 13 terms ?</h3>
The first term(a) is 2
The common difference(d) is 3
n= 13
The formular is
n/2(2a + (n-1)d)
= 13/2 [ 2(2) + (13-1)3]
= 6.5 [4 + 12(3)]
= 6.5 [4 + 36]
= 6.5(40)
= 260
Hence the sum of the first 13 terms is 260
Read more on sequence here
brainly.com/question/8824658?referrer=searchResults
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Common denominator:
(r-2g)/g =-8j/g==> r-2g=-8j
Solve for j, ==> -8j = r-2g & j=(r-g)/(-8) or j= (g-r)/8
Answer:
a. y = 6
b. RS = 44
ST = 37
RT = 81
Step-by-step explanation:
RS = 7y + 2
ST = 5y + 7
RT = 14y - 3
find:
a. y
b. RS, ST, RT
RS + ST = RT
7y + 2 + 5y + 7 = 14y - 3
group like terms
7y + 5y + 2 + 7 = 14y - 3
12y + 9 = 14y - 3
9 + 3 = 14y - 12y
12 = 2y
y = 12/2
y = 6
-----------------------------------
b.
RS = 7(6) + 2
RS = 44
ST = 5(6) + 7
ST = 37
RT = 14(6) - 3
RT = 81
Answer:
-4 2/21
Step-by-step explanation:
-2 3/7 - 1 2/3
Change to improper fraction
-2 3/7 = -17/7
- 1 2/3 =-5/3
-17/7-5/3
L.C.M=21
-51-35/21
= -86/21
= -4 2/21
Hope it helps..
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