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UkoKoshka [18]
3 years ago
7

Which is a description of phishing?

Computers and Technology
1 answer:
kodGreya [7K]3 years ago
7 0

Answer:

C. sending emails impersonating legitimate companies in an attempt to learn a recipient's personal information

You might be interested in
Write a program whose input is two integers. Output the first integer and subsequent increments of 5 as long as the value is les
adell [148]

Answer:

Following are the code to the given question:

For code 1:

start = int(input())#defining a start variable that takes input from the user end

end = int(input())#defining a end variable that takes input from the user end

if start > end:#use if that checks start value greater than end value

   print("Second integer can't be less than the first.")#print message

else:#defining else block

   while start <= end:#defining a while loop that checks start value less than equal to end value

       print(start, end=' ')#print input value

       start += 5#incrementing the start value by 5

   print()#use print for space

For code 2:

while True:#defining a while loop that runs when its true

   data = input()#defining a data variable that inputs values

   if data == 'Done' or data == 'done' or data == 'd':#defining if block that checks data value

       break#use break keyword

   rev = ''#defining a string variable rev

   for ch in data:#defining a for loop that adds value in string variable  

       rev = ch + rev#adding value in rev variable

   print(rev)#print rev value

Explanation:

In the first code two-variable "first and end" is declared that takes input from the user end. After inputting the value if a block is used that checks start value greater than end value and use the print method that prints message.

In the else block a while loop is declared that checks start value less than equal to end value and inside the loop it prints input value and increments the start value by 5.

In the second code, a while loop runs when it's true and defines a data variable that inputs values. In the if block is used that checks data value and use break keyword.

In the next step, "rev" as a string variable is declared that uses the for loop that adds value in its variable and prints its values.

3 0
3 years ago
The batteries on electric vehicles are recharged using electricity from either a wall socket or dedicated charging unit.
yuradex [85]

Answer:

true

Explanation:

7 0
2 years ago
For the past five days, the Howard family has traveled these miles: 389;126;419;93; and 394. Find the range and how. Show all yo
Fofino [41]
The answer is 326.

Range is found by subtracting the smallest number in the data set from the largest number.

Highest number: 419
Lowest number: 93

419-93
=326

(Next time make sure to post this under the Mathematics section.)
5 0
3 years ago
1. Scrieţi un program care citeşte un număr natural n şi determină produsul cifrelor impare ale lui n. De exemplu, pentru n = 23
saveliy_v [14]

Answer:

1.  

num1 = input("Enter the value of n")  

n = int(num1)  

def calc(n):  

Lst = []  

while n > 0:  

remainder = n % 10  

Lst.append(remainder)  

quotient = int(n / 10)  

n = quotient  

i = len(Lst) - 1  

sum = 1  

for i in range(0, len(Lst)):  

if(i % 2 != 0):  

sum *=Lst[i];  

else:  

continue  

print(sum)  

return(0)  

\ r2

num=input("Enter the value of n")

arr=[12,-12,13,15,-34,-35,35,42]

def div7positive():

  sum = 0

  m = 0

  i = 0

  while m <= 7:

      if(arr[i]>=0 and arr[i]%7 == 0):

          sum +=arr[i]

      i = i + 1

      m += 1

       

   

  print("sum of number divisible by 7 and positive is", +sum);

div7positive()

\ r

\ r3.Write an algorithm that reads a natural number n and calculates the sum:

\ rS = 1 / (1 * 2) + 1 / (2 * 3) + 1 / (3 * 4) +… + 1 / ((n-1) * n)

\ r

num=input("Enter the value of n")

def sumseries():

  sum = 0

  m= 0

  while m <= 7:

      sum +=1/((int(num)-1)*int(num))

      m += 1

  print("sum of series is", +sum)

sumseries()

\ R4. Read a natural number n. Calculate the sum of its own divisors n. For example, for n = 12, the sum of its own divisors is 2 + 3 + 4 + 6 = 15

num=input("Enter the value of n")

def sumdivisors():

  sum = 0

  m= 2

  while m <= int(num):

      if int(num) % m == 0:

          sum += m

      m += 1

  print("sum of divisors is", +sum)

sumdivisors()\ r

\ R5. We read a natural number n and then whole numbers. Calculate and display the sum of the natural numbers between 10 and 100. For example, if n = 5 and then read 30, –2, 14, 200, 122, then the sum will be 44 (that is, 30 + 14).

\ r

Lst = []  

num=input("Enter the value of n")

i = 0

while i<= int(num):

  num1=input("Enter the element of array")

  Lst.append(int(num1));

  i += 1

def numbet0and100():

  sum = 0

  m= 0

  while m <= int(num):

      if Lst[m] <= 100 or Lst[m] >=0:

          sum += Lst[m]

      m += 1

  print("sum of numbers between 0 and 100 is", +sum)

numbet0and100()

\ R6. A natural number n of maximum 4 digits is read. How many digits are in all numbers from 1 to n? For example, for n = 14 there are 19 digits, and for n = 9 there are 9 digits.

\ r

num = input("Enter the value of n")

n = int(num)

print(“sum as required is:” (n -9) + n)  

 

\ R7. Read the natural numbers n and S, where n can be 2, 3, 4 or 5. Show all the numbers of n digits that have the numbers in strictly ascending order, and the sum of the digits is S. For example, for n = 2 and S = 10, 19, 28, 37, 46 will be displayed.

num = input("Enter the value of n")

n = int(num)

Lst = []

def calc(n):

  i = 1

  total = pow(10,n)

  while i <= total:

      j = i

      while j > 0:

          remainder = j % 10  

          Lst.append(remainder)

          quotient = int(j / 10)

          if quotient > 0:

              j = quotient

          else:

              length = len(Lst) - 1

              sum = 0

              while length >= 0:

                  sum += Lst[length]

                  length = length - 1

              if sum == pow(10,n):

                  print(j)

              k = len(Lst)

              del Lst[0:k]

      i = i + 1

  return(0)

calc(n)

\ r

\ R8. We consider the row 1, 1, 2, 3, 5, 8, 13, ... in which the first two terms are 1, and any other term is obtained from the sum of the preceding two. Write an algorithm that reads a natural number n and displays the first n terms of this string. For example, for n = 6, 1, 1, 2, 3, 5, 8 will be displayed.

\ r

nterm = int(input("What number of terms do you want?"))

a, b = 0, 1

totalcount = 0

if nterm <= 0:

 print("Please input a positive number")

elif nterm == 1:

 print("Fibonacci number upto which",nterm,":")

 print(a)

else:

 print("Fibonacci series:")

 print(nterm)

 while totalcount < nterm:

     print(a)

     nth = a + b

     a = b

     b = nth

     totalcount += 1

 

\ 9. Write an algorithm that reads two natural numbers n1 and n2 and displays the message "yes" if the sum of the squares of the digits of n1 is equal to the sum of the numbers of n2 or "no" otherwise. For example, for n1 = 232 and n2 = 881, "yes" will be displayed, and for n1 = 45 and n2 = 12, "no" will be displayed.

num1 = input("Enter the value of n")

num3 = input("Enter the value of n")

n = int(num1)

num2 = int(num3)

def calc(n):

  Lst = []

  while n > 0:

      remainder = n % 10  

      Lst.append(remainder)

      quotient = int(n / 10)

      n = quotient

       

  i = len(Lst) - 1

  sum = 0

  while i >= 0:

      sum += Lst[i]* Lst[i]

      i = i - 1

  return(sum)

def calc1(num2):

  Lst = []

  while num2 > 0:

      remainder = num2 % 10  

      Lst.append(remainder)

      quotient = int(num2 / 10)

      num2 = quotient

       

  i = len(Lst) - 1

  sum = 0

  while i >= 0:

      sum = Lst[i] + Lst[i]

      i = i - 1

  return(sum)

a = calc(n)

b = calc1(num2)

if a == b:

  print("yes")

else:

  print("No")

\ r

\ R10. Write an algorithm that reads a natural number n and displays the message "yes" if all of its n numbers are distinct, or "no" if n does not have all the distinct digits. For example, for n = 37645 it will display "yes" and for 23414 it will show "no".

\ r

num1 = input("Enter the value of n")

n = int(num1)

def calc(n):

  Lst = []

  while n > 0:

      remainder = n % 10  

      Lst.append(remainder)

      print( remainder)

      quotient = int(n / 10)

      n = quotient

       

  flag = 1

  for i in range(0, len(Lst)):

      for j in range(i+1, len(Lst)):    

          if Lst[i] == Lst[j]:    

              flag = 0

              break

           

  if flag == 1:

      print("YES")

  else:

      print("NO")

  return(0)

Explanation:

Please check answer.  

3 0
2 years ago
For the LEGv8 assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j ar
lana66690 [7]

Answer:

Response:<em> B[g]= A[f]+ A[f + 1]; </em>

<em>Explanation: </em>

• The very first command "LSL, X9, X0, #3" was to multiply the factor "f" by "8" use the shift function, this really is essential to get 8-byte words from the arrays.  

• The next command was to enter the array element "A" with index "f," the index of A[f] would be in' X9' from the first instruction implementation.

• The third and fourth instructions are the same as first and second statements however the array will be "B" and the index will be "g"

• The fifth statement "LDUR X0,[ X9, #0]" will assign the array value in "A[f]" to the variable "f" located in X0.

• The sixth command "ADDI X11, X9, #8" should lead in the next array value being stored after the "X11" address "A[f]," which is the value of the item A[f+1].  

• The next command "LDUR X9,[ X11,#0]" would be to load the command to "X9."  

• The next "ADD X9, X9, X0" instruction results in the addition of X0 with X9 contents, i.e. A[f] and A[f+1] array contents, resulting in X9 register.  

• During the last request, the value stored in X9 is stored in X10, assigned to the address of B[ g] • Therefore, the overall operation performed by the instructions given is: B[g]= A[f]+ A[f + 1]

Therefore, the related C statement is B[g]= A[f]+ A[f + 1].

7 0
3 years ago
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