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One mole of CH₄ reacts with<em> two moles </em>of O₂, producing <em>one mole</em> of CO₂ and<em> two moles</em> of H₂O. Also, one molecule of CH₄ reacts with<em> two molecules </em>of O₂, producing one molecule of CO₂ and<em> two molecules </em>of H₂O.
<h3>
Balance chemical equation</h3>
A balanced chemical equation tells the amounts of reactants and products needed to satisfy the Law of Conservation of Mass.
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (g).
From the chemical combustion of methane given above, One mole of CH₄ reacts with<em> two moles </em>of O₂, producing <em>one mole</em> of CO₂ and<em> two moles</em> of H₂O. Also, one molecule of CH₄ reacts with<em> two molecules </em>of O₂, producing one molecule of CO₂ and<em> two molecules </em>of H₂O.
Find out more on Balance chemical equation at: brainly.com/question/15355912
I'm not good at math but im going to take a wild guess and say its 280 degrees
hey buddy here is your answer
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Using sum and difference identities from trigonometric identities shows that; Asin(ωt)cos(φ) +Acos(ωt)sin(φ) = Asin(ωt + φ)
<h3>How to prove Trigonometric Identities?</h3>
We know from sum and difference identities that;
sin (α + β) = sin(α)cos(β) + cos(α)sin(β)
sin (α - β) = sin(α)cos(β) - cos(α)sin(β)
c₂ = Acos(φ)
c₁ = Asin(φ)
The Pythagorean identity can be invoked to simplify the sum of squares:
c₁² + c₂² =
(Asin(φ))² + (Acos(φ))²
= A²(sin(φ)² +cos(φ)²)
= A² * 1
= A²
Using common factor as shown in the trigonometric identity above for Asin(ωt)cos(φ) +Acos(ωt)sin(φ) gives us; Asin(ωt + φ)
Complete Question is;
y(t) = distance of weight from equilibrium position
ω = Angular Frequency (measured in radians per second)
A = Amplitude
φ = Phase shift
c₂ = Acos(φ)
c₁ = Asin(φ)
Use the information above and the trigonometric identities to prove that
Asin(ωt + φ) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)
Read more about Trigonometric Identities at; brainly.com/question/7331447
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