Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...
126/42=378/126=1134/378=3
The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:
42=a(3)^(2-1)
42=3a
a=14
So the first term is 14.
Answer:
Option B.
Step-by-step explanation:
Note: The function f(x) is not in correct format it must be
.
It is given that two different plants that grow each month at different rates are represented by the functions f(x) and g(x).
Let as consider the two functions,


Now, table of values is
Month(x)

1 3 17
2 9 22
3 27 27
4 81 32
From the above table it is clear that in first and second month the height of the f(x) plant is less than of g(x).
In month 3, heights are equal.
In month 4, height of the f(x) plant exceed that of the g(x) plant.
Therefore, the correct option is B.
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
What is the value of this expression when c = -4 and d = 10 ?
(c³ + d²)
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
(c³ + d²) where c = -4 and d = 10
<h3>To Find:-</h3>
The value of the expression
(c³ + d²)
<h2>Solution:-</h2>
(c³ + d²) [Given expression]
Now, putting the value of c = -4 and d = 10 , we get,
{ (-4)³ + (10)² }
( -64 + 100 )
( 36 )
× 36

Answer:
A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function
Step-by-step explanation: