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alekssr [168]
3 years ago
10

Determine the quadrant where θ lies given that sinθ < 0 and tanθ > 0.

Mathematics
2 answers:
tino4ka555 [31]3 years ago
4 0
The answer to this question is quadrant III. Since
sinθ = y/r and tanθ = y/x, we have, in quadrant III, x, y negative.

sinθ < 0 (r always positive) but tanθ > 0 (negative divided by negative is positive).
cricket20 [7]3 years ago
3 0

Answer:

Option c. is correct.

Step-by-step explanation:

if sin\theta < 0 means values of sin\theta will be negative.

For tan\theta =\frac{sin\theta }{cos\theta } > 0 means  positive value of tan\theta

values of sin\theta and cos\theta  both should be either > 0 or < 0 for the poitive values of tan\theta. If any one, sine or cosine is negative then tan\theta will be < 0

We know that for the condition tan\theta > 0 and sin\theta < 0 value of cos\theta should be negative.

Therefore, \theta should lie in 3rd quadrant where sin\theta and cos\theta both are negative.

Option C. 3rd option is correct.

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Find the first term of the following geometric sequence ----,42,126,378,1,134
sergey [27]
Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...

126/42=378/126=1134/378=3

The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:

42=a(3)^(2-1)

42=3a

a=14

So the first term is 14.
8 0
3 years ago
Question 8 Multiple Choice Worth 1 points)
bogdanovich [222]

Answer:

Option B.

Step-by-step explanation:

Note: The function f(x) is not in correct format it must be f(x)=3^x.

It is given that two different plants that grow each month at different rates are represented by the functions f(x) and g(x).

Let as consider the two functions,

f(x)=3^x

g(x)=5x+12

Now, table of values is

Month(x)        f(x)=3^x           g(x)=5x+12

    1                      3                          17

    2                     9                         22

    3                     27                        27

    4                     81                        32

From the above table it is clear that in first and second month the height of the f(x) plant is less than of g(x).

In month 3, heights are equal.

In month 4, height of the f(x) plant exceed that of the g(x) plant.

Therefore, the correct option is B.

4 0
3 years ago
What is the value of this expression when c=-4 and d = 10?<br> 1/4(c3+d2)
Mumz [18]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

What is the value of this expression when c = -4 and d = 10 ? \frac{1}{4} (c³ + d²)

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

\frac{1}{4} (c³ + d²) where c = -4 and d = 10

<h3>To Find:-</h3>

The value of the expression \frac{1}{4} (c³ + d²)

<h2>Solution:-</h2>

\frac{1}{4} (c³ + d²) [Given expression]

Now, putting the value of c = -4 and d = 10 , we get,

\frac{1}{4} { (-4)³ + (10)² }

\frac{1}{4} ( -64 + 100 )

\frac{1}{4} ( 36 )

\frac{1}{4} × 36

\bf = \: 9 \: ( Answer )

3 0
3 years ago
two girls have 76$ between them. if they first gave the second $7 they would each have the same amount of money. how much did ea
Rainbow [258]
Each girl had a total of $10.85
4 0
3 years ago
Determine whether or not the relation is a function. Please help asap
OLga [1]

Answer:

A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function

Step-by-step explanation:

4 0
2 years ago
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