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Agata [3.3K]
2 years ago
8

Mr. T's Tea store has two kinds of tea. Tea A costs $9 per pound and Tea B cost $6 per pound. How many pounds of each should be

combined to obtain 150 pounds of tea worth $8 per pound? ​
Mathematics
1 answer:
harina [27]2 years ago
3 0

Answer:

y=447.3 pounds

x= 297.3 pounds

Step-by-step explanation:

Step one:

given data

Tea A costs $9 per pound and

Tea B cost $6 per pound.

let the number of pounds of Tea A be x

and for Tea B be y pounds

The total cost of the mixture = $8 per pound

hence

9x+6y=8---------1

The total weight of the mixture

150 pounds

x+y=150-----------2

Step two:

9x+6y=8---------1

x+y=150---------2

from eqn 2 x=150-y

put x= 150-y in eqn 1

9(150-y)+6y=8---------1

1350-9y+6y=8

1350-8=9y-6y

1342=3y

divide both sides by 3

y= 1342/3

y=447.3 pounds

put y= 447.3 in eqn 2

x+447.3= 150

x= 150-446=7.3

x= -297.3

x= 297.3 pounds

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<u>x                     y               xy               x²                 y²</u>

14                   12              168            196              144

1                      3                 3               1                   9

6                     6                 36            36                 36

5                     7                 35             25                49

10                    7                 70             100              49

6                      8                 48             36              64

11                      9                99             121               81

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