Mr. T's Tea store has two kinds of tea. Tea A costs $9 per pound and Tea B cost $6 per pound. How many pounds of each should be combined to obtain 150 pounds of tea worth $8 per pound?
1 answer:
Answer:
y=447.3 pounds
x= 297.3 pounds
Step-by-step explanation:
Step one:
given data
Tea A costs $9 per pound and
Tea B cost $6 per pound.
let the number of pounds of Tea A be x
and for Tea B be y pounds
The total cost of the mixture = $8 per pound
hence
9x+6y=8---------1
The total weight of the mixture
150 pounds
x+y=150-----------2
Step two:
9x+6y=8---------1
x+y=150---------2
from eqn 2 x=150-y
put x= 150-y in eqn 1
9(150-y)+6y=8---------1
1350-9y+6y=8
1350-8=9y-6y
1342=3y
divide both sides by 3
y= 1342/3
y=447.3 pounds
put y= 447.3 in eqn 2
x+447.3= 150
x= 150-446=7.3
x= -297.3
x= 297.3 pounds
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