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Crank
4 years ago
5

Alma en peso ajugar ala ora que marca el reloj qué eran las 3 :45pm y terminó alas 5pm cuánto tiempo Jugo alma Alma empezó a jug

ar a la hora que marca el reloj que eran las 3:45 pm y termino a las 5 pm cuánto tiempo jugó alma
Mathematics
1 answer:
anzhelika [568]4 years ago
4 0

Answer:

01:55:55

Step-by-step explanation:

1 horas 55 minutos 55 segundos

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63.09 ÷ .00008<br><br>No rush on this, but if you know please respond, it will be appreciated.​
mart [117]
Answer is 788, 625. Hope this helped!
3 0
3 years ago
Discuss three contributing factors that led to the human violations of human trafficking​
kenny6666 [7]

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Three contributing factors that led to human trafficking

Political instability, militarism, civil unrest, internal armed conflict and natural disasters may result in an increase in trafficking. The destabilization and displacement of populations increase their vulnerability to exploitation and abuse through trafficking and forced labour.

7 0
3 years ago
A model rocket is launched with an initial velocity of 240 ft/s. The height, h, in feet, of the rocket t seconds after the launc
Setler [38]

Answer:

About 1.85 seconds and 13.15 seconds.

Step-by-step explanation:

The height (in feet) of the rocket <em>t</em> seconds after launch is given by the equation:

h = -16t^2 + 240 t

And we want to determine how many seconds after launch will be rocket be 390 feet above the ground.

Thus, let <em>h</em> = 390 and solve for <em>t: </em>

<em />390 = -16t^2  +240t<em />

Isolate:

-16t^2 + 240 t - 390 = 0

Simplify:

8t^2 - 120t + 195 = 0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2 -4ac}}{2a}

In this case, <em>a</em> = 8, <em>b</em> = -120, and <em>c</em> = 195. Hence:

\displaystyle t = \frac{-(-120)\pm \sqrt{(-120)^2 - 4(8)(195)}}{2(8)}

Evaluate:

\displaystyle t = \frac{120\pm\sqrt{8160}}{16}

Simplify:

\displaystyle t = \frac{120\pm4\sqrt{510}}{16} = \frac{30\pm\sqrt{510}}{4}

Thus, our two solutions are:

\displaystyle t = \frac{30+ \sqrt{510}}{4} \approx  13.15 \text{ or } t  = \frac{30-\sqrt{510}}{4} \approx 1.85

Hence, the rocket will be 390 feet above the ground after about 1.85 seconds and again after about 13.15 seconds.

4 0
3 years ago
Find the rate as a ratio of distance to time 369 km , 3 sec simplify answer
Nuetrik [128]
Rate or velocity is always distance divided by time

369 km / 3 sec =
123 kilometers per second


6 0
3 years ago
I need some help. Please
Ilya [14]

Are you able to ask your teacher?

7 0
3 years ago
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