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Ira Lisetskai [31]
4 years ago
8

A rectangle is 10 cm longer than it is wide. If its length and width are both decreased by 2 cm, its area

Mathematics
1 answer:
Grace [21]4 years ago
8 0

Answer:

Step-by-step explanation:

Yeah it right thank sweetheart

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A race at travels at a rate of 205 mph how far would it travel in 3 hours?
Liono4ka [1.6K]
615 miles, because you do 205*3
8 0
3 years ago
HELP ASAP WITH THIS QUESTION
alexgriva [62]
Hey there (again)

x = 2y  \\ y = -2  \\ x = 2(-2) \\x= -4 \\ \\ \\ w + xy + 4x^2  = 2\\ w+-4(-2) + 3(-4)^2 = 2 \\ w + 8 + 3(16) = 2 \\ w + 8 + 48 = 2 \\ Subtract56: w + 56 =2 \\ 56 - 56 (Cancel) \\ 2 - 56 = -54 \\ w = -54

Answer: B  the simplification performed in step 2 is invalid or incorrect

Good luck on your assignment and enjoy your day 

~MeIsKaitlyn:)
5 0
4 years ago
Which of the following is not equal to cos⁡(520°)?
Gnoma [55]
The cosine repeats itself every 360 degrees, and it mirrors at 0 and 180 degrees. It inverts around 90 and 270.
So without using a calculator, you can tell that:

cos(520)=cos(520-360)=cos(160)
cos(160) = cos(180-20) = cos(180+20) = cos(200)
cos(160) is NOT equal to cos(20), it would be -cos(20).
cos(160) = -cos(20) = -cos(-20)

So C is the only one unequal.
8 0
3 years ago
Read 2 more answers
In a couple of sentences and in your own words describe in what ways horizontal, vertical, and oblique asymptotes can be identif
drek231 [11]
A horizontal asymptote is one in which y has a limit as x approaches positive or negative infinite. It is usually due to both the denominator and the numerator having the same highest degree term, and the coefficient created by their proportion serves as the asymptote. For example, (2x^2 + 1) / (3x^2) would have a horizontal asymptote of 2/3

A vertical asymptote is an x value at which y approaches infinite. One example includes when the denominator of the function approaches zero at a certain point. For example, (x^2 + 3) / (x + 1) has a vertical asymptote at x=-1, since the denominator approaches zero as x approaches this point. 

For an oblique asymptote, y generally takes the form of a linear function as x approaches infinite. This is the case when the highest term in numerator is one degree higher than the highest degree term in the denominator. 

Examples include (5x^2 + 2) over 2x, where the oblique asymptote is (5/2)x, and even the linear function 2x+3 has an oblique asymptote of 2x
5 0
4 years ago
Please help me solve. x-(-16)=44 i know the answer i just need the work
Marat540 [252]

x+16=44

x=44-16

x=28

That is the answer

6 0
3 years ago
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