Solve the following equation 7a-9=12
2 answers:
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Hi!
When you break the rule for the first time, de probability distribution of X is constant in [0, 2], and is zero outside. If the the value obtained is X = a, then the probability distribution of Y (conditioned on X = a) is constaint in interval [0, a], and zero outside. Then the region in the X-Y plane where the joint density is non-zero is the filled triangle in the figure.
I would cut the "h" into parts
Now you have 3 parts to work with
2 times 6 = 12
2 times 2 = 4
2 times 6 = 12
Add them all up
Area = 28 squared
Now you have 3 parts to work with
2 times 6 = 12
2 times 2 = 4
2 times 6 = 12
Add them all up
Area = 28 squared