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babunello [35]
3 years ago
10

Let m be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x2+y2=49, 0≤z≤1, and a hemispher

ical cap defined by x2+y2+(z−1)2=49, z≥1. for the vector field f=(zx+z2y+8y, z3yx+5x, z4x2), compute ∬m(∇×f)⋅ds in any way you like.
Mathematics
1 answer:
maxonik [38]3 years ago
3 0

It seems that the boundary of M is the circle x^2+y^2=49 in the plane z=0. By Stokes' theorem,

\displaystyle\iint_M(\nabla\times\vec f)\cdot\mathrm d\vec S=\int_{\partial M}\vec f\cdot\mathrm d\vec r

Parameterize \partial M by

\vec r(t)=(7\cos t,7\sin t,0)

with 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\partial M}\vec f(x(t),y(t),z(t))\cdot\mathrm d\vec r=\int_0^{2\pi}(56\sin t,35\cos t,0)\cdot(-7\sin t,7\cos t,0)\,\mathrm dt

=\displaystyle\int_0^{2\pi}(245\cos^2t-392\sin^2t)\,\mathrm dt=\boxed{-147\pi}

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