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meriva
3 years ago
11

2 A golfer hit a golf ball from a tee box that is 6 yards above the ground. The graph shows the

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:b

Step-by-step explanation:

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Can you add 4√10 and 4√6 together? If so, what is the answer?
Mnenie [13.5K]

Answer:

No, because the radicands are not the same

Step-by-step explanation:

7 0
3 years ago
Order these three values from least to greatest. Explain or show your reasoning.
enot [183]

The correct answer is 82% of 50 (41) / 170% of 30 (51) /65% of 80 (52)

Explanation:

The first step to know whether a value is greater than another is to find the value each percentage represents depending on the total. This process is shown below.

1. 65% of 80- This implies 80 is 100% and 85% needs to be found. Use the following formula:

80 / 100 = 0.8 x 65 = 52 or the total number divided by 100 and multiplied by the percentage you want to know

2. 82% of 50 - Repeat the same process

50 / 100 = 0.5 x 82 = 41

3. 170% of 30

30 / 100 = 0.3 x 170 = 51

4. Finally organize the values

82% of 50 (41)

170% of 30 (51)

65% of 80 (52)

8 0
3 years ago
Read 2 more answers
Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S
Sophie [7]

Answer:

Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that A=J^{-1}AJ. Thus, A↔A.

<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP).

Recall that if P and Q are invertible, then QP is invertible and (QP)^{-1}=P^{-1}Q^{-1}. So, if we denote R=QP we obtained that

A=R^{-1}CR. Hence, A↔C.

Therefore, the relation is an <em>equivalence relation</em>.

4 0
4 years ago
Find the inverse of the function f(x) = 5/6x +10
UkoKoshka [18]

Answer:

\displaystyle f^{-1}(x)=\frac{6x-60}{5}

Step-by-step explanation:

<u>Inverse function</u>

Given the function

\displaystyle f(x)=\frac{5}{6}x+10

We find its inverse following the procedure below:

  • Set y=f(x)

\displaystyle y=\frac{5}{6}x+10

  • Multiply by 6:

6y=5x+60

  • Operate:

5x=6y-60

  • Solve for x:

\displaystyle x=\frac{6y-60}{5}

  • Swap variables:

\displaystyle y=\frac{6x-60}{5}

  • Make the new y the inverse function:

\boxed{\displaystyle f^{-1}(x)=\frac{6x-60}{5}}

This is the inverse function

4 0
3 years ago
The gravitational force produced between any two objects kept 2.5×10^4 km apart is 580 N . At what distance should they be kept
DochEvi [55]

Answer:

Formula for gravitational force    F = G M1 * M2 / R^2  where G is the gravitational constant

F2 / F1 = (R1 / R2)^2 = 1/2         where F2 is the required force

R2 = (2)^1/2  R1     distance for R2 to be 1/2 force at R1

Since force is proportional to the square of the distance of separation, increasing the distance of separation by 2^2 will halve the force

7 0
3 years ago
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