Question

What is the equation of a line which includes points (-5, 5) and (2, 5)?

Answer 1

Hello!

The answer is:

The equation of the line which includes the points (-5,5) and (2,5) is:

$y=5$

Why?

To find the line which includes the points (-5,5) and (2,5) we can use the following equation:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}*(x-x_1)$

So, using the points (-5,5) and (2,5), we have:

$y-5=\frac{5-5}{2-(-5)}*(x-(-5))$

$y-5=\frac{0}{2+5}*(x-(-5))$

$y-5=0*(x+5)$

$y-5=0$

$y=5$

We have that the equation of the line which includes the points (-5,5) and (2,5) is:

$y=5$

Have a nice day!

Note: I have attached a picture for better understanding.