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3 years ago

The LAST QUESTION PLEASE HELP

Mathematics

1 answer:

Vladimir [108]3 years ago

4 0

Step-by-step explanation:

Waves have the form:

y = A sin (2π/T x + φ) + B

where A is the amplitude (the distance from the center of the wave to the max or min),

T is the period (time it takes for one cycle),

φ is the phase shift (moves the wave left or right),

and B is the offset (moves the wave up or down).

This can also be written with cosine.

Here, we have d = 6 cos(π/2 t).

The amplitude is A = 6, so the maximum distance from the equilibrium position is 6 units.

The period is:

2π / T = π/2

T = 4

So the period is 4 seconds.

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3 years ago

Find the measure of angle A. 4x 135° 5x A

Mkey [24]

<h2>Using this equation:</h2>

 $4 \times + 5 \times + 135 = 180$ 

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2 years ago

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4 years ago

How would you find the quadratic that goes through the point (4,0), the axis of symmetry is x=7, and it also goes through the po

nasty-shy [4]

9514 1404 393

Answer:

y = (5/27)(x -7)^2 -5/3

Step-by-step explanation:

Use the given points to find the unknowns in the equation.

If the axis of symmetry is x=7, then the equation can be written in the form ...

y = a(x -7)^2 +b

Filling in the two point values, we have two equations:

0 = a(4 -7)^2 +b ⇒ 9a +b = 0

5 = a(1 -7)^2 +b ⇒ 36a +b = 5

Subtracting the first equation from the second, we have ...

(36a +b) -(9a +b) = (5) -(0)

27a = 5

a = 5/27

Substituting that value into the first equation gives ...

9(5/27) +b = 0

5/3 +b = 0

b = -5/3

So, the quadratic can be written in vertex form as ...

y = (5/27)(x -7)^2 -5/3

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3 years ago