All categories

4 years ago

5. Solve the equation. 8/x+3 = 1/x+1

Mathematics

1 answer:

Helga [31]4 years ago

4 0

Answer:

x = -5/7

Step-by-step explanation:

8 1

---------- = ----------

x+3 x+1

Using cross products

8 (x+1) = 1 (x+3)

Distribute

8x+8 = x+3

Subtract x from each side

8x-x +8 = x-x+3

7x+8 =3

Subtract 8 from each side

7x +8-8 =3-8

7x = -5

Divide each side by 7

7x/7 = -5/7

x = -5/7

You might be interested in

PLEASE HELPPP MEEEEEEEEEEE I DK THIS-

Julli [10]

Answer:

FOr the first one you can do:

y= -x +4

y= -x+2

y = -x

y= -x-2

y = x-4

Step-by-step explanation:

I'll do the second one in a different answer use these for now.

8 0

3 years ago

Two opposite sides of a parallelogram are 3x-8 and 10x+13. Find the measure of all sides

RSB [31]

Answer:

Step-by-step explanation:

Using the parallelogram theorem

3x-8 = 10x+13

-7x = 21

x = -3

Substitute

3(-3) - 8

-17

10(-3) + 13

-17

5 0

3 years ago

Nina decided to raise money for a community organization that provides free classes and legal

Over [174]

A percentage is a way to describe a part of a whole. The money that is raised by Nina in the second month is $960.

<h3>What are Percentages?</h3>

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

Given that the money raised by Nina in the first month is $800, while the money raised by Nina in the second month is 20% more.

Therefore, the money raised by Nina in the second month is,

Money raised = $800 + 20% of $800

= $800 + 0.20($800)

= $800 + $160

= $960

Hence, the money that is raised by Nina in the second month is $960.

Learn more about Percentages here:

brainly.com/question/6972121

#SPJ1

8 0

2 years ago

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago

The side of a square measures (3x − 6) units. Part A: What is the expression that represents the area of the square? Show your w

liubo4ka [24]

A. The area of a square is given as:

A = s^2

Where s is a measure of a side of a square. s = (2 x – 5) therefore,

A = (2 x – 5)^2

Expanding,

A = 4 x^2 – 20 x + 25

B. The degree of a polynomial is the highest exponent of the variable x, in this case 2. Therefore the expression obtained in part A is of 2nd degree.

Furthermore, polynomials are classified according to the number of terms in the expression. There are 3 terms in the expression therefore it is classified as a trinomial.

C. The closure property demonstrates that during multiplication or division, the coefficients and power of the variables are affected while during multiplication or division, only the coefficients are affected while the power remain the same.

4 0

3 years ago