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Crank
3 years ago
12

What is the radius of the circle? The circumference is 615.44.

Mathematics
2 answers:
pentagon [3]3 years ago
8 0

Answer: 98

Step-by-step explanation:

C=2\pi r

Solve for r;

r=\frac{C}{2\pi}

r=\frac{615.44}{2(3.14)} \\r=98

diamong [38]3 years ago
7 0
If the circumference is 6.15.44 all you need to do is divide by 2 which is 97.95.
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Step-by-step explanation:

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Step-by-step explanation:

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7 0
4 years ago
Show that if f(n) is O(g(n)) and d(n) is O(h(n)) then f(n) + d(n) is O(g(n) + h(n)).
GaryK [48]
f(n)\in\mathcal O(g(n)) is to say

|f(n)|\le M_1|g(n)|

for all n beyond some fixed n_1.

Similarly, d(n)\in\mathcal O(h(n)) is to say

|d(n)|\le M_2|h(n)|

for all n\ge n_2.

From this we can gather that

|f(n)+d(n)|\le|f(n)|+|d(n)|\le M_1|g(n)|+M_2|h(n)|\le M(|g(n)|+|h(n)|)

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M(|g(n)|+|h(n)|)\le2M\max\{|g(n)|,|h(n)|\}

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3 0
3 years ago
What are the common factors of 50 30 100
lesya [120]
Their common factors are :1, 2 ,5 ,10
5 0
3 years ago
What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?
german
For this case we have the following function:
 f(x) =  tan(\frac{x^2}{9})
 The average rate of change is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2- x1}
 Evaluating the function for the given interval we have:
 For x = 1.25:
 f(1.25) = tan(\frac{1.25^2}{9})
 f(1.25) = 0.18
 For x = 2:
 f(2) = tan(\frac{2^2}{9})
 f(2) = 0.48
 Then, replacing values we have:
 AVR = \frac{0.48 - 0.18}{2 - 1.25}
 AVR = 0.4
 Answer:
 
the average value of on the closed interval [1.25, 2] is:
 
AVR = 0.4



3 0
3 years ago
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