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Andrews [41]
2 years ago
6

Vector u = <11, 12>, v = <-16, 6>, and w = <4, -5>. Match each vector operation with its resultant vector expr

essed as a linear combination of the unit vectors i and j.

Mathematics
1 answer:
MAVERICK [17]2 years ago
5 0

3u - 2v + w gives the resultant vector as; <49, 19>

8u - 6v gives the resultant vector as; <184, 60>

7v - 4w gives the resultant vector as; <61, 104>

u - 5w gives the resultant vector as; <-9, 37>

<h3>How to find the resultant of vectors?</h3>

We are given the vectors;

u = 11i + 12j

v = -16i + 6j

w = 4i - 5j

1) 3u - 2v + w gives the resultant vector as;

3(11i + 12j) - 2(-16i + 6j) + 4i - 5j

⇒ 33i + 36j + 32i - 12j + 4i - 5j

⇒ 49i + 19j

⇒ <49, 19>

2) 8u - 6v gives the resultant vector as;

8(11i + 12j) - 6(-16i + 6j)

⇒ 88i + 96j + 96i - 36j

⇒ 184i + 60j

3) 7v - 4w gives the resultant vector as;

7(11i + 12j) - 4(4i - 5j)

⇒ 77i + 84j - 16i + 20j

⇒ 61i + 104j

4) u - 5w gives the resultant vector as;

11i + 12j - 5(4i - 5j)

11i + 12j - 20i + 25j

-9i + 37j

Read more about Resultant Vectors at; brainly.com/question/110151

#SPJ1

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The options aren't given, however, the range of amount spent could be calculated

Answer:

Kindly check explanation

Step-by-step explanation:

Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amounts that could be the price of the dvd

Given that :

DVD costs the same amount

Number of DVD's = 3

Cost of cds = 10

Number of cds = 7

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Highest price :

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Step-by-step explanation:

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Unghiurile ∢AOB, ∢BOC, ∢COD și ∢DOA sunt unghiuri în jurul punctului O, ∢AOB = 80°, ∢BOC = 140° și CO ⊥ OD.
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Answer:

a) ∡AOC = 140 °

∡AOD = 40 °

b) ∡AOB = ∡BOC + ∡AOC și ∡BOC = ∡AOC (unghiuri formate din segmentul OC) prin urmare, segmentul OC bisectează ∡AOB

Step-by-step explanation:

a) Calculați măsurile unghiurilor ∢AOC și ∢AOD.

b) Arătați că jumătatea liniei opuse jumătății liniei OC este bisectoarea unghiului ∢AOB

a) Parametrii dați sunt;

∡AOC. ∡BOC. ∡COD și ∡DOA sunt unghiuri în jurul circumferinței unui cerc

∡AOB = 80 ° și ∡BOC = 140 °, segmentul CO este perpendicular pe segmentul DO

Prin urmare, avem;

∡AOB + ∡BOC + ∡AOC = 360 ° (Suma unghiurilor într-un punct = 360 °)

∴ ∡AOC = 360 ° - (∡AOB + ∡BOC) = 360 ° - (80 ° + 140 °) = 140 °

  ∡AOC = 140 °

∡BOC + ∡BOD = 180 ° (Suma unghiurilor unui triunghi = 180 °)

∡BOD = 180 ° - ∡BOC = 180 ° - 140 ° = 40 °

∡BOD = 40 °

∡ BOD + ∡AOD = ∡AOB

∡AOD = ∡AOB - ∡BOD = 80 ° - 40 ° = 40 °

∡AOD = 40 °

b) Deoarece avem ∡AOB = ∡BOC + ∡AOC și ∡BOC = ∡AOC = 140 °, avem;

∡AOB = 140 ° + 140 ° = 280 ° = 2 × ∡BOC = 2 × ∡AOC

Prin urmare, segmentul OC bisectează ∡AOB

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