Question

Question 31 (Essay Worth 5 points)

Answer 1

For this case we have by definition, that the derivative of the position with respect to time is the velocity, that is to say:

$\frac {d (s (t))} {dt} = v (t)\\\frac {d (6-14t)} {dt} = v (t)$

So:

Taking into account that the derivative of a constant is 0.

$\frac {d (6-14t)} {dt} = 0- (1 * 14 * t ^ {1-1}) = 0- (14 * t ^ 0) = - 14$

So, the velocity is -14

Answer:

-14