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poizon [28]
3 years ago
12

In the division problem, what does the 8 represent in the quotient 3653÷13=281

Mathematics
1 answer:
Bumek [7]3 years ago
4 0
A 8 thirteens !!!!!!!!
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Can someone explain this to me??
SOVA2 [1]

Answer:

Yes. g⁻¹(x) = f(x).

Step-by-step explanation:

Let y = ∛x - 1.

Rearrange to solve for x:

y+1 = ∛x

(y+1)³ = x

Swap x and y:

(x+3)³ = y

g⁻¹(x) = (x+3)³ = f(x)

8 0
3 years ago
What is the sum of 16x^3 – 5x– 2 and 6x^2 +3x+ 5?
Yuri [45]

Answer: 6x^2

Step-by-step explanation:

3 0
3 years ago
Please help asap!!!!!!
RSB [31]

Answer:

z = 66

Step-by-step explanation:

QT is a midsegment. Thus, applying the midsegment theorem:

RS = 2(QT)

QT = z - 33,

RS = z

Plug in the values into the equation

z = 2(z - 33)

z = 2z - 66

Subtract 2z from each side

z - 2z = -66

-z = -66

Divide both sides by -1

z = 66

5 0
3 years ago
30 POINTS IF ANSWERED IN THE NEXT FIVE MINUTES. Ms. Roth has made 200 headbands and is deciding what price to charge for them. S
gizmo_the_mogwai [7]

Answer:

198.5

Step-by-step explanation:

() = 200 - 1.5

() = 198.5

im not sure if this is what you are asking, but i hope it helps

8 0
3 years ago
ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 -
TiliK225 [7]

Answer:

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

5 0
3 years ago
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