Afirm works 7 days a week. Every employee must work exactly 3 full days and 4 half-days each week. A half-day can be either morn
ing or afternoon, and two half-days cannot be held on the same day. a) How many possible different weekly schedules are there? 560 Expected answer: 560
You just need to solve for x in the equation: –0.01x^2 + 0.32x + 4 = <span>–0.01x^2 + 0.18x + 5 0.18x=1 x= 5.55 h(5.55) = -0.01*30.86+0.18*5.55+5 = -0.3086+1+5=5.6914
The intersection point is (5.55, 5.69). I hope that this is the answer that you were looking for and it has helped you. </span>
