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valentinak56 [21]
3 years ago
5

Afirm works 7 days a week. Every employee must work exactly 3 full days and 4 half-days each week. A half-day can be either morn

ing or afternoon, and two half-days cannot be held on the same day. a) How many possible different weekly schedules are there? 560 Expected answer: 560
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

  a)  560 (as you know)

Step-by-step explanation:

There are 7C3 = 35 ways to choose 3 full-time days from 7.

There are 2^4 = 16 ways to choose a half-day each day from the remaining 4 days.

The total number of possible schedules is ...

  35×16 = 560

_____

nCk = n!/(k!(n-k)!)

7C3 = 7·6·5/(3·2·1) = 7·5 = 35

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geniusboy [140]
Well, should be likee thiss correct meh if im wrong or what ever, but
 the answer would be, last one (x + 8)(x - 8), well 1, is because the 64 is a negative so if you would just take that 64 and bring it down then look at this onece the work is donee then when u add the 2 numbers that x would be x² or x2 n  that - 64 is that + 8 (-8) witch would equal out so if you really look at it the CORRECT ANSWER WOULD BE B. (x - 8)(x -8)


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3 years ago
Which of the following is the equation of a line perpendicular to the line
Taya2010 [7]

Answer:

  • A. - 2x + 3y = 21

Step-by-step explanation:

The perpendicular lines have opposite reciprocal slopes.

<u>The given line has a slope of:</u>

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<u>And its y-intercept is:</u>

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<u>Convert this into standard form and compare with answer choices:</u>

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Correct choice is A

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2 years ago
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otez555 [7]

Answer:

a = 8

Step-by-step explanation:

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I hope this helps a little bit.

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Answer:

Step-by-step explanation:

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