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3 years ago

1.draw a scatter plot that shows a positive, linear association and has one clear outlier. Circle the outlier

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

Step-by-step explanation:

Here is the correct answer.See the pic

Ps:Can I be the brainliest.Thx

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Work out 3/4 + 4/7 what is the answer to this question

worty [1.4K]

Answer:

1 and 9/28

Step-by-step explanation:

you need to put everything over the same denominator

21/28+16/28=37/28

this can be written as 1 9/28

7 0

3 years ago

Rob buys a rocking chair priced at 27$. if the sales tax is 10%, what will be the total cost including tax?

seraphim [82]

Answer:

$29.7

Step-by-step explanation:

10 percent of 27 is 2.7 then you add 27 and 2.7 and you get 29.7

8 0

2 years ago

Four students were discussing how to find the unit rate for a proportional relationship.Which method is valid?

jenyasd209 [6]

Answer:use a calculator

Step-by-step explanation:

6 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

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we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

Ms. Lackey gave each student in her class a calculator.Each calculator weighed 16 ounces. If Ms.Lackey gave each of her 20 stude

jeka94

Everyone got a calculator.....each weighed 16 oz.......gave them to 20 students.....20 * 16 = 320 total oz

16 oz = 1 lb

320/16 = 20 lbs <==

or, if u just think about it...u gave 16 oz to each student.....16 oz = 1 lb...so u gave 1 lb to each student....20 students = 20 lbs

4 0

3 years ago