A right rectangular prism is shown.

Mrs. Rodriquez has 24 students in her class. Ten of the students are boys. Jeff claims that the ratio of boys to girls in this c

iVinArrow [24]

Answer:

Jeff found the ratio of boys to students. He needed to first find that there are 14 girls to get a ratio of 10:14 or 5:7.....answer is the first one

Step-by-step explanation:

brainly.com/question/5872696

4 0

4 years ago

A garbage company recycles ½ tons of plastic every 3 minutes. At this rate, approximately how many tons of plastic does the comp

Sauron [17]

Answer:

Total number of minutes in 2 days = 2880

Total time used for recycling garbage in 2 days = 2880/3 = 960

If 3 minutes = 1/2 tons

Then 960 minutes = 960*1/2 = 960/2 = 480

Therefore <u>480</u> tons of garbage where recycled in 2 days

3 0

3 years ago

Simplify the following expressions. Cross out the letter that matches your answer.

OverLord2011 [107]

1. 3x + 5x + 14x = 22x

2. 4x + 7 + 11x = 15x+7

3. 10x + 8 - 3x= 7x+8

4. 6x - 5 + X - 11 = 7x-16

5. -8x + 19 + 2 - 2x = -10x+21

6. X + 23 + 4x - 34 - X = 4x-11

7. 105 + 27x - 68 - 19x - 27 + x = 9x +10

8. 7x + 16 - 3x + 3 - 2x - 2x = 19

9. -18 + 6 - 4x + 10 - 11x + 2 = -15x

10. 16 + 4x - 12x - 28 - 6x + 17 + x - 1 = -13x+4

8 0

3 years ago

Car X travels 186 miles and 3 hours right the equation of the line that describes the relationship between distance and time

irga5000 [103]

Answer:

Y=62x

Step-by-step explanation:

7 0

3 years ago

A researcher has developed a new drug designed to reduce blood pressure. In an experiment, 21 subjects were assigned randomly to

Paladinen [302]

Answer:

Step-by-step explanation:

Hello!

The objective of the research is to compare the newly designed drug to reduce blood pressure with the standard drug to test if the new one is more effective.

Two randomly selected groups of subjects where determined, one took the standard drug (1- Control) and the second one took the new drug (2-New)

1. Control

X₁: Reduction of the blood pressure of a subject that took the standard drug.

n₁= 23

X[bar]= 18.52

S= 7.15

2. New

X₂: Reduction of the blood pressure of a subject that took the newly designed drug.

n₂= 21

X[bar]₂= 23.48

S₂= 8.01

The parameter of study is the difference between the two population means (no order is specified, I'll use New-Standard) μ₂ - μ₁

Assuming both variables have a normal distribution, there are two options to estimate the difference between the two means using a 95% CI.

1) The population variances are unknown and equal:

[(X[bar]₂-X[bar]₁)± $t_{n_1+n_2-2;1-\alpha /2}$ *( $Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ )]

$t_{n_1+n_2-2;1-\alpha /2}= t_{23+21-2;1-0.025}= t_{42;0.975}= 2.018$

$Sa=\sqrt{\frac{(n_1-1)*S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{22*7.15^2+20*8.01^2}{42} }= 7.57$

[23.48-18.52]±2.018*( $7.57*\sqrt{\frac{1}{21} +\frac{1}{23} }$ )]

[0.349; 9.571]

2) The population variables are unknown and different:

Welche's approximation:

[(X[bar]₂-X[bar]₁)± $t_{Dfw;1-\alpha /2}$ *( $\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} }$ )]

$Df_{w}= \frac{(\frac{S_1^2}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S_1^2}{n_1} )^2}{n_1-1}+ \frac{(\frac{S_2^2}{n_2} )^2}{n_2-1} } = \frac{(\frac{7.15^2}{23} +\frac{8.01^2_2}{21} )^2}{\frac{(\frac{7.15^2}{21} )^2}{20}+ \frac{(\frac{8.01^2}{23} )^2}{22} } = 42.85= 42$

$t_{Df_w;1-\alpha /2}= t_{42; 0.975}= 2.018$

[(23.48-18.52)±2.018 $\sqrt{\frac{7.15^2}{23} +\frac{8.01^2}{21} }$ ]

[0.324; 9.596]

I hope this helps!

4 0

3 years ago