Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
Answer:
A exterior angle of a polygon is an angle outside the polygon formed by one of its sides and the extension of an adjacent side.
Answer:
The least common factor is 18
Step-by-step explanation:
- what you need to do is subtract 56 - 38 = 18
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Answer:
8 inches
Step-by-step explanation:
To find the area of a triangle, we use the formula
A = 1/2 bh where b is the length of the base and h is the height
A = 24 and b = 6
24 = 1/2 (6) * h
24 =3h
Divide each side by 3
24/3 = 3h/3
8 =h
The height is 8 inches