It takes 3 copies of 1/6 to show the same amount as 1 copy of 1/2 because 3 copies of 1/6 would add up to 3/6 thus making it 1/2
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
Answer:
97
Step-by-step explanation:
83 and JKL form a straight line so they add to 180 degrees
83+ JKL = 180
Subtract 180 from each side
83-83+ JKL = 180-83
JKL = 97
