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Neporo4naja [7]
3 years ago
12

Expression is equivalent to 5(6x+3y)

Mathematics
2 answers:
otez555 [7]3 years ago
8 0
I think the answer is d
Olenka [21]3 years ago
3 0
5(6x + 3y) = 30x + 15y (Answer D)
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Can someone please help me? I can't find the h(x) for 0. I also need help with the last question. Please I need it very soon.
Solnce55 [7]

9514 1404 393

Answer:

  see attachments for a table and graph

Step-by-step explanation:

I find it convenient to use a graphing calculator or spreadsheet to do repetitive computations reliably.

__

Your specific question asks for h(0):

  h(0) = -|0 +2| +1 = -2 +1

  h(0) = -1

You may want to check your other table values.

8 0
3 years ago
"Ralphie has 23 more toys than his little brother Joey. If they were to get all of their toys out and lay them on the floor,
Ivahew [28]

Answer:

c the bottom is incorrect

Step-by-step explanation:

if you take ralphie who has 23 more toys than his brother and subtract his brothers toys your going to get the extra 23.

6 0
3 years ago
the participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men an
Nostrana [21]

Answer:

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = \frac{56}{1024} = 0.0546

Step-by-step explanation:

The participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men and women

That is probability of participants of television quiz of equal numbers of men and women that is 50 %of men and 50% of women.

p = 50/100 = 1/2

q = 1-p = 1 - 1/2 = 1/2

n =10

we will use binomial distribution p(x =r) = n_{cr} p^{r} q^{n-r}

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = P(x=0)+P(x=1)+P(x=2)

          = 10_{c0} \frac{1}{2} ^{0} (\frac{1}{2}) ^{10-0}+ 10_{c1} \frac{1}{2} ^{1} (\frac{1}{2}) ^{10-1   \\   + 10_{c2} \frac{1}{2} ^{2} (\frac{1}{2}) ^{10-2

          by using formula n_{cr} =\frac{n!}{(n-r)!r!}

on simplification we get

     = 10_{c0}  (\frac{1}{2}) ^{10}+ 10_{c1} (\frac{1}{2}) ^{10) + 10_{c2} (\frac{1}{2}) ^{10)

    = 1  (\frac{1}{2}) ^{10}+ 10(\frac{1}{2}) ^{10)+45  (\frac{1}{2}) ^{10}

  = \frac{56}{1024} = 0.0546

<u>Conclusion</u>:-

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = \frac{56}{1024} = 0.0546

8 0
3 years ago
A pair of sunglasses on sale for 30% off original price.if the original Price is $18.00 what is the sale price?
Zanzabum
The sales price is $5.40
4 0
3 years ago
Read 2 more answers
Solve the radical equation.
Scrat [10]

Answer:

there are no extraneous solutions to the equation

Step-by-step explanation:

Given

\sqrt{8x+9} = x + 2 ( square both sides )

8x + 9 = (x + 2)² ← expand

8x + 9 = x² + 4x + 4 ( subtract 8x + 9 from both sides )

0 = x² - 4x - 5 ← in standard form

0 = (x - 5)(x + 1) ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 1 = 0 ⇒ x = - 1

As a check

Substitute these values into the equation and if both sides are equal then they are the solutions.

x = 5 : \sqrt{8(5)+9} = \sqrt{49} = 7

right side = 5 + 2 = 7

left side = right side ⇒ x = 5 is a solution

x = - 1 : \sqrt{8(-1)+9} = \sqrt{1} = 1

right side = - 1 + 2 = 1

left side = right side ⇒ x = - 1 is a solution

There are no extraneous solutions

4 0
3 years ago
Read 2 more answers
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