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ZanzabumX [31]
3 years ago
13

I NEED THIS NOWW!!!!!!

Mathematics
2 answers:
miskamm [114]3 years ago
6 0
Check the picture below.

coming straight up from Dave's house at y=-12, up to y = 0 is 12 units, then we keep on going up up to y = 8, 12 + 8, so to get to John's house, is 20 units off the grid.

then they take off to the swimming pool, from x = -16, up to x = -4, what's that difference?   is 12 units, | 16 - 4| = 12.

so, Dave went 20 units to John's house, and then 12 units to the swimming pool.

20 + 12, or 32 units.

borishaifa [10]3 years ago
6 0
(-16,-12) to (-16,8) is 20 units then from (-16,8) to (-4,8) is 12 units so 20+12= 32units
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Mary purchased a prepald phone card for $30. Long distance calls cost 8 cents a minute using this card. Mary used her card only
julia-pushkina [17]
Hey can I have brainlyist I only need one more :)
4 0
2 years ago
Solve and show your work<br><br> 1. -3(x - 2) &lt;1/3
Nutka1998 [239]

Answer:

x>17/9

Step-by-step explanation:

-3(x-2) < 1/3

-3x+6 < 1/3

-3x < 1/3-6

-3x < -17/3

x > 17/9

3 0
3 years ago
10 points!!!!! Do 14 and 15 only hurry please.
Aleksandr [31]

Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

8.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

                x = 31 - 15 =  16

9.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

           (6x - 4)° = 56°

            6x = 56 + 4

               6x = 60

                 x = 10

14.

13x + 5x = 180°                       [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180°                       [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

m ∠RSU = 4(28) + 12 = 112 + 12 = 124°

m ∠UST = 2(28) = 56°

3 0
3 years ago
Read 2 more answers
The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio
zzz [600]

Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

a)

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

b)

i) SD = 0.65

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

c)

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

d)

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

4 0
3 years ago
Helpppp plzzz The frequency histogram shows the lengths of trails in a large park.
Rus_ich [418]

Answer:

13 trails

Step-by-step explanation:

The histogram shows following numbers of trails:

  • <u>0 - 6 km long</u> - 5 trails;
  • 6 - 12 km long - 9 trails;
  • 12 - 18 km long - 7 trails;
  • 18 - 24 km long - 3 trails;
  • <u>24 - 30 km long</u> - 4 trails;
  • <u>30 - 36 km long</u> - 1 trail;
  • <u>36 - 42 km long</u> - 3 trails.

So, there are 5 trails with length less than 6 km and 4 + 1 + 3 = 8 trails that are at least 24 km long.

In total, 5 + 8 = 13 trails

8 0
3 years ago
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