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2 years ago

I NEED THIS NOWW!!!!!!

Mathematics

2 answers:

miskamm [114]2 years ago

6 0

Check the picture below.

coming straight up from Dave's house at y=-12, up to y = 0 is 12 units, then we keep on going up up to y = 8, 12 + 8, so to get to John's house, is 20 units off the grid.

then they take off to the swimming pool, from x = -16, up to x = -4, what's that difference? is 12 units, | 16 - 4| = 12.

so, Dave went 20 units to John's house, and then 12 units to the swimming pool.

20 + 12, or 32 units.

borishaifa [10]2 years ago

6 0

(-16,-12) to (-16,8) is 20 units then from (-16,8) to (-4,8) is 12 units so 20+12= 32units

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Part A

labwork [276]

An algebraic expression is one that consists of both number(s) and an alphabet(s). The required answers are:

i. Distance from Chenoa's house to the coffee shop = 6.0 miles

ii. Distance from coffee shop to Chenoa's school = 1.5 miles

iii. Distance from Chenoa's house to her school = 7.5 miles

An algebraic expression is one that consists of both number(s) and an alphabet(s). The alphabet is referred to as the unknown whose value has to be determined.

In the given question, let the distance from the coffee shop to Chenoa's school be represented by y.

So that;

The distance from Chenoa's house to the coffee shop = (2y + 3) miles.

The total distance from Chenoa's house to her school = 5y.

This implies that:

(2y + 3) + y = 5y

3y + 3 = 5y

3 = 5y - 3y

2y = 3

y = $\frac{3}{2}$

= 1.5

The distance from the coffee shop to Chenoa's school is 1.5 miles.

Thus;

(2y + 3) = ( 2(1.5) + 3)

= 6

The distance from Chenoa's house to the coffee shop is 6 miles.

And,

5y = 5(1.5)

= 7.5

The total distance from Chenoa's house to her school is 7.5 miles.

For more clarifications on algebraic expressions, visit: brainly.com/question/12792264

#SPJ1

5 0

2 years ago

What radius of a circle is required to inscribe a regular hexagon with an area of 210.44 cm2 and an apothem of 7.794 cm

alekssr [168]

We know that

[area of a regular hexagon]=6*[area of one equilateral triangle]
210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²

[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm

the length side of a regular hexagon is 9 cm
applying the Pythagorean theorem
r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm

this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)

the answer is
the radius is 9 cm

8 0

3 years ago

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IRINA_888 [86]

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5 0

2 years ago

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