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3 years ago

PLEASE HELP!!!!!!!!!!!!!!

Mathematics

2 answers:

alex41 [277]3 years ago

5 0

Im not sure im so sorry

Tomtit [17]3 years ago

4 0

Grab a calculator, and per each person, add how much is in their bank, wallet, and piggy bank, i’ll give you a start. $110.50 + 30$ + 47.20$ = 187.70$

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Each month the census bureau mails survey forms to 250,000 households asking questions about the people living in the household

DENIUS [597]

The sample is the 240,000 households that respond. The correct option among all the options that are given in the question is the second option or option "B". The other choices are incorrect and can be easily negated. i hope that this is the answer that your were looking for and it has come to your great help.

7 0

3 years ago

What is 5 to the second power plus 2 the the fifth power plus 1

Flura [38]

The answer is 58 .

5x5=25
2x2x2x2x2=32
25+32=57
57+1=58

5 0

3 years ago

Read 2 more answers

Negative one-half(–4a – 6) + a2 for a = 8

stepladder [879]

Answer:

Leon multiplied 8 by 2 when he should have raised 8 to a power of 2.

The multiplication of two negative values in step 4 should result in a positive value.

The correct answer should be 83.

Step-by-step explanation:

I did it i was correct

3 0

3 years ago

School is making digital backups of old reels of film in its library archives the table shown approximate run Times of the films

Gemiola [76]

One technique that you can apply when solving such a problem is trial and error. We try to use each equation to prove that a given value of x on the table given will correspond to the value of y on the table.

a) Let's try to put x = 3 for the first equation and we must get an answer equal to 2.25.

$y=7.72(3)-29.02=-5.86_{}$

Since the value of y is not equal to 2.25 and the deviation is too large. this equation is not a good model,

b) We put x = 3 on the second equation and solve for y

$y=-7.52(3)^2+0.19(3)+3.26=-63.85$

Since the value of y is not equal to 2.25 and the deviation is too large. this equation is not a good model,

c) We put x = 3 on the third equation and solve for y,

$y=0.4(3)^2+0.79(3)-4.93=1.04$

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of x. If x = 5, we get

$y=0.4(5)^2+0.79(5)-4.93=9.02$

which has a slight deviation on the given value of y on the table for x = 5. let's try for x = 7. We have

$y=0.4(7)^2+0.79(7)-4.93=20.2$

and the answer has a small deviation compared to the actual value given. The other values of x can again be put on the equation and check their corresponding value of y, and the resulting values are as follows

$\begin{gathered} y=0.4(8)^2+0.79(8)-4.93=26.99 \\ y=0.4(12)^2+0.79(12)-4.93=62.15 \\ y=0.4(14)^2+0.79(14)-4.93=84.53 \end{gathered}$

And as you can see, the deviation of values from the table to calculated becomes smaller. Hence, this is the best model.

d) We put x = 3 on the third equation and solve for y,

$y=4.19(1.02)^3=4.45_{}_{}$

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of x. If x = 5, we get

$y=4.19(1.02)^5=4.63$

where the answer's deviation is too large compared to the value of y if x = 5 on the table given.

Based on the calculations used above, the best equation that can be a good model is equation 3.

5 0

1 year ago

When you convert from a large unit such as pounds or minutes to a smaller unit as ounces or seconds why do you use multiplicatio

Ronch [10]

Hope this helps:))))))

6 0

3 years ago