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3 years ago

If the annual interest rate is 12%, what is the monthly interest rate?

Mathematics

2 answers:

nordsb [41]3 years ago

4 0

1. A

2. C

3. D

4. A

5. B

Hope this helps

vovangra [49]3 years ago

4 0

1. a
2. b
3. d
4. c
5. c
I just took the quiz, I promise this is correct.

You might be interested in

What number multiplied by itself 3 times equal 343

ratelena [41]

7 because 7 • 7 = 49 • 7 = 343

6 0

3 years ago

Read 2 more answers

SOMEONE PLEASE HELP ME ON QUESTIONS 17-19 I NEED ASAP

Lana71 [14]

Answer:

17. 10x+24 OR 108 18. 72 19. 8.4

Step-by-step explanation:

(10x+24)+72=180

10x+96=180

10x=84

x=8.4

10x+24

10(8.4)+24

84+24

108

8 0

3 years ago

Can someone please answer this please!

DaniilM [7]

Answer:

T = ±22

Step-by-step explanation:

Let's solve your equation step-by-step.

0=−16t2+7744

Step 1: Add 16t^2 to both sides.

0+16t2=−16t2+7744+16t2

16t2=7744

Step 2: Divide both sides by 16.

16t2

7744

t2=484

Step 3: Take square root.

t=±√484

t=22 or t=−22

6 0

3 years ago

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon

fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that $n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0

3 years ago

If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align=

boyakko [2]

Answer:

Solution given:

f(x) = $\frac{1}{9}$ x-2

let f(x)=y

y = $\frac{1}{9}$ x-2

interchanging role of x and y

x= $\frac{1}{9}$ y-2

x+2= $\frac{1}{9}$ y

y=9(x+2)

y=9x+18

F-¹(x)=9x+18

and

F-¹(-1)=9*-1+18=-9+18=9

6 0

3 years ago