Answer:
No solution.
Step-by-step explanation:
Absolute value cannot be less than 0
Answer:
<h2><em><u>126</u></em></h2>
Step-by-step explanation:
<em>In</em><em> </em><em>number</em><em> </em><em>4</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>figure</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>parallelogram</em><em>, </em>
<em><u>So</u></em><em><u>,</u></em>
Base of the parallelogram = 14
Height of the parallelogram = 9
<em><u>Therefore</u></em><em><u>, </u></em>
Area of the parallelogram = <em><u>Base</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>Height</u></em><em><u> </u></em>
= 14 × 9
= 126
<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>figure</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>no</u></em><em><u>.</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>12</u></em><em><u>6</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
3 seconds
0= -16t^2+144
-144/-16=9
9=t^2
Sq rt of 9 is 3
In both cases you may well benefit from graphing the functions.
Do you recognize f(x) = (x + 1)^2 - 1 as a quadratic function, whose graph is that of a parabola that opens up? By comparing this to y = a(x-h)^2 + k, we see that a=1, h= -1 and k = -1. The vertex is at (h,k), which here is the point (-1, -1). This is the minimum value of the function. Thus, the range of this function is [-1, infinity).
Now for the function f(x) = 7x - 11: This is a linear function whose graph is (surprise!) a straight line. When x increases, y increases, without limits to either. Similarly, when x decreases, y decreases.
Thus the range includes all real numbers: (-infinity, infinity).
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